Proof of Restriction of a Second-Order Equation Operator to an Open Subset
lemmalem:operator-restriction-2026aEach assertion is read off from the corresponding definition, the point being that every quadruple whose first entry lies in the smaller set is a quadruple for the original operator, at which the two operators agree.
Conventions. From the setting we use only the real numbers, Euclidean space with its distance and notion of openness, and the set with its ordering and distance . Throughout, implies , and for every such and all , , .
Proof of claim 1. By the definition of a second-order equation operator, an operator on is a function from to , where is an open subset of . The set is open by hypothesis, and is by construction a function on that set of quadruples with values in , so it is a second-order equation operator on .
Proof of claim 2. Assume is degenerate elliptic, and let , , and satisfy . Since , degenerate ellipticity of gives , that is
As , , , and were arbitrary, is degenerate elliptic.
Proof of claim 3. Assume is continuous at and let be positive. By clause Continuity of a Second-Order Equation Operator Β§at-point there is a positive such that all , , and satisfying
also satisfy . Every lies in , and agrees with at every quadruple with first entry in ; hence the same witnesses the required condition for , and is continuous at .
Finally, if is continuous, that is continuous at every quadruple in the sense of clause Continuity of a Second-Order Equation Operator Β§continuous, then in particular it is continuous at every quadruple whose first entry lies in , so is continuous at every such quadruple; these are exactly the quadruples at which continuity of is required.
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Prerequisites
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