Proof of The Compensated Poisson Process is a Square-Integrable Martingale
theoremthm:compensated-poisson-martingale-2026aThroughout, is on and off ; expectations are handled with Linearity and Monotonicity of the Lebesgue Integral; closure and measurability facts (sums, differences with constants, products) are the preliminaries of Square-Integrable Random Variables and the Mean-Square Inner Product, which apply verbatim with any sub--algebra in place of ; and is the natural filtration, to which is adapted by that definition.
Step 1 (conditions (i) and (ii) of the martingale definition). By condition 3 of Stochastic Process, Independent Increments, and Inhomogeneous Poisson Process with and , for the variable has the Poisson distribution with parameter ; by Moments of the Poisson Distribution it is square-integrable with . For , is square-integrable. Constants are square-integrable on a probability space, so each is square-integrable; and is -measurable, being the difference of the -measurable variable and a constant. Hence is a stochastic process, adapted to , with square-integrable values: conditions (i) and (ii) of Square-Integrable Martingale, Submartingale, and Supermartingale hold.
Step 2 (the increment is independent of the past). Fix and set , a random variable (as recorded in Stochastic Process, Independent Increments, and Inhomogeneous Poisson Process) with the Poisson distribution with parameter by condition 3 of that definition; by Moments of the Poisson Distribution, is integrable with . We claim that the -algebras and are independent.
Let consist of together with all sets of the form with , real , and Borel sets . This family is a -system: intersections of two such sets merge into one after taking the union of the time points and intersecting the Borel sets attached to shared time points (inserting at time points missing from one of the two). Every generator of with lies in or differs from a member by the constant variable , whose level sets are or ; and every member of lies in . By minimality of the generated -algebra, .
Fix and a Borel set ; we show the product formula . Consider the grid , refined by inserting if , and let be the increments of over the consecutive intervals of the grid starting from time , so that and . By condition 2 of Stochastic Process, Independent Increments, and Inhomogeneous Poisson Process, the family is independent. Index it by and apply Grouping Lemma for Independent Random Variables with the two disjoint blocks and : the -algebras and are independent. For each , pointwise where is the position of in the grid; sums of -measurable variables are measurable with respect to that -algebra (preliminaries of Square-Integrable Random Variables and the Mean-Square Inner Product applied with this -algebra), so each , and hence , lies in . The independence of the two -algebras (product formula of Sigma-Algebra Generated by Random Variables and Independence of Sigma-Algebras with two factors) now gives the claimed product formula; for it is trivial.
Next, fix a Borel set and let
Exactly as in Step 3 of the proof of Grouping Lemma for Independent Random Variables (with the single fixed event in the role of the fixed intersection there), is a -system: it contains ; it is closed under relative complements for by finite additivity; and it is closed under nondecreasing countable unions by countable additivity and the algebra of limits. It contains by the previous paragraph, so Dynkin's Pi-Lambda Theorem gives . Since was arbitrary, and the one-factor cases of the product formula are trivial, the pair , is independent in the sense of Sigma-Algebra Generated by Random Variables and Independence of Sigma-Algebras.
Step 3 (the averaged martingale identity). Fix and . The pair , is independent: for Borel sets , the event lies in and is one of , each in ; the required product formulas are instances of the independence established in Step 2 (with inserted for omitted factors). Both and are integrable, so Expectation of a Product of Independent Random Variables gives
Pointwise , and all four products are integrable, so linearity and give
For the identity is trivial. Hence the martingale property in averaged form of Square-Integrable Martingale, Submartingale, and Supermartingale holds, which by that definition is equivalent to condition (iii). Together with Step 1, is a square-integrable martingale with respect to .
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Prerequisites
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