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Proof of The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields

lemmalem:product-field-projection-properties-wasserstein-2026a
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· 7,356 chars · 17 deps · depth 37 Reason: Phase N1a proof.

The pairing identity holds on gradients by the definition of the projection and extends to the tangent space by density and the norm identity for product fields; Cauchy-Schwarz with g equal to the projection gives the contraction, and splitting inner products over the particles gives the product-field identity.

Proof

Each result cited is universally quantified over the data in its own statement. Write μ=P[1]∈P2(Rd)\mu=P^{[1]}\in\mathcal{P}_{2}(\mathbb{R}^{d}). The spaces L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) and L2(P;RdN)L^{2}(P;\mathbb{R}^{dN}) of Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §fields are real Hilbert spaces, in particular real inner product spaces, so The Cauchy-Schwarz Inequality in a Real Inner Product Space applies in each; their elements are classes of Borel maps, with the operations of The Space of Square-Integrable Random Vectors §classes applied as in that clause. Block maps pk\mathfrak{p}_{k}, configurations and product maps are those of Particle Blocks of the Configuration Space: Block Maps, Configurations, Product Maps and Diagonal Points with q=p=dq=p=d, and t\sqrt{t} is the nonnegative square root of Existence and Uniqueness of the Nonnegative Square Root.

Step 1 (Norms and differences of product fields). Let g,h∈L2(μ;Rd)g,h\in L^{2}(\mu;\mathbb{R}^{d}). By Product Fields and the Projection onto One-Particle Tangent Fields §product-field, ∥g⊕∥P2=N∥g∥μ2=(N∥g∥μ)2\lVert g^{\oplus}\rVert_{P}^{2}=N\lVert g\rVert_{\mu}^{2}=(\sqrt{N}\lVert g\rVert_{\mu})^{2}, and both ∥g⊕∥P\lVert g^{\oplus}\rVert_{P} and N∥g∥μ\sqrt{N}\lVert g\rVert_{\mu} are nonnegative, so ∥g⊕∥P=N∥g∥μ\lVert g^{\oplus}\rVert_{P}=\sqrt{N}\lVert g\rVert_{\mu} by the uniqueness in Existence and Uniqueness of the Nonnegative Square Root. Let g~,h~\tilde g,\tilde h be Borel representatives of g,hg,h; then g~+(−1)h~\tilde g+(-1)\tilde h is a Borel representative of g−hg-h by The Space of Square-Integrable Random Vectors §classes. For x∈RdNx\in\mathbb{R}^{dN}, the product map of Particle Blocks of the Configuration Space: Block Maps, Configurations, Product Maps and Diagonal Points §product-map and Particle Blocks: Linearity, Splitting of Inner Products, Product Maps and Diagonal Shifts §linear (with t=−1t=-1) give

(g~+(−1)h~)⊕(x)=[g~(p1(x))+(−1)h~(p1(x)),… ]=g~⊕(x)+(−1) h~⊕(x).(\tilde g+(-1)\tilde h)^{\oplus}(x)=\bigl[\tilde g(\mathfrak{p}_{1}(x))+(-1)\tilde h(\mathfrak{p}_{1}(x)),\dots\bigr]=\tilde g^{\oplus}(x)+(-1)\,\tilde h^{\oplus}(x).

Taking classes, (g−h)⊕=g⊕−h⊕(g-h)^{\oplus}=g^{\oplus}-h^{\oplus} by Product Fields and the Projection onto One-Particle Tangent Fields §product-field and The Space of Square-Integrable Random Vectors §classes; hence ∥g⊕−h⊕∥P=N∥g−h∥μ\lVert g^{\oplus}-h^{\oplus}\rVert_{P}=\sqrt{N}\lVert g-h\rVert_{\mu}.

Step 2 (Pairing against gradients). Let D∈L2(P;RdN)D\in L^{2}(P;\mathbb{R}^{dN}) and ψ∈Cc∞(Rd)\psi\in C_{c}^{\infty}(\mathbb{R}^{d}). Multiplying the identity of Product Fields and the Projection onto One-Particle Tangent Fields §projection by NN gives ⟨D,(∇ψ)⊕⟩P=N⟨ΠP(D),∇ψ⟩μ\langle D,(\nabla\psi)^{\oplus}\rangle_{P}=N\langle\Pi_{P}(D),\nabla\psi\rangle_{\mu}. Thus claim 1 holds for every gg in the set GμG_{\mu} of The Tangent Space of the Wasserstein Space at a Probability Measure §gradients.

Step 3 (Claim 1). Let D∈L2(P;RdN)D\in L^{2}(P;\mathbb{R}^{dN}) and g∈Tμg\in T_{\mu}, and put Δ=⟨D,g⊕⟩P−N⟨ΠP(D),g⟩μ\Delta=\langle D,g^{\oplus}\rangle_{P}-N\langle\Pi_{P}(D),g\rangle_{\mu} and C=N∥D∥P+N∥ΠP(D)∥μ≥0C=\sqrt{N}\lVert D\rVert_{P}+N\lVert\Pi_{P}(D)\rVert_{\mu}\ge0. Let ε>0\varepsilon>0. Since TμT_{\mu} is the closure of GμG_{\mu} in L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) (The Tangent Space of the Wasserstein Space at a Probability Measure §tangent), Characterization of the Closure in a Metric Space by Open Balls (claim 1 implies claim 3) gives h∈Gμh\in G_{\mu} with ∥g−h∥μ<ε\lVert g-h\rVert_{\mu}<\varepsilon. By Step 2 for hh, bilinearity of the inner products and Step 1,

Δ=⟨D,(g−h)⊕⟩P−N⟨ΠP(D),g−h⟩μ,\Delta=\bigl\langle D,(g-h)^{\oplus}\bigr\rangle_{P}-N\langle\Pi_{P}(D),g-h\rangle_{\mu},

so by The Cauchy-Schwarz Inequality in a Real Inner Product Space in both spaces and Step 1, ∣Δ∣≤∥D∥PN∥g−h∥μ+N∥ΠP(D)∥μ∥g−h∥μ≤Cε|\Delta|\le\lVert D\rVert_{P}\sqrt{N}\lVert g-h\rVert_{\mu}+N\lVert\Pi_{P}(D)\rVert_{\mu}\lVert g-h\rVert_{\mu}\le C\varepsilon. If Δ≠0\Delta\ne0, the choice ε=∣Δ∣(C+1)−1>0\varepsilon=|\Delta|(C+1)^{-1}>0 would give ∣Δ∣≤C(C+1)−1∣Δ∣<∣Δ∣|\Delta|\le C(C+1)^{-1}|\Delta|<|\Delta| (Elementary Order Arithmetic in an Ordered Field, claims 7 and 10), which is impossible. Hence Δ=0\Delta=0, which is claim 1.

Step 4 (Linearity). Let D,D′∈L2(P;RdN)D,D'\in L^{2}(P;\mathbb{R}^{dN}) and a,b∈Ra,b\in\mathbb{R}, and put ζ=aΠP(D)+bΠP(D′)\zeta=a\Pi_{P}(D)+b\Pi_{P}(D'). Then ζ∈Tμ\zeta\in T_{\mu}, since TμT_{\mu} is a linear subspace by Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §closed, and for every ψ∈Cc∞(Rd)\psi\in C_{c}^{\infty}(\mathbb{R}^{d}) the defining identity of Product Fields and the Projection onto One-Particle Tangent Fields §projection for DD and D′D' and bilinearity give

⟨ζ,∇ψ⟩μ=aN⟨D,(∇ψ)⊕⟩P+bN⟨D′,(∇ψ)⊕⟩P=1N⟨aD+bD′,(∇ψ)⊕⟩P.\langle\zeta,\nabla\psi\rangle_{\mu}=\frac{a}{N}\bigl\langle D,(\nabla\psi)^{\oplus}\bigr\rangle_{P}+\frac{b}{N}\bigl\langle D',(\nabla\psi)^{\oplus}\bigr\rangle_{P}=\frac{1}{N}\bigl\langle aD+bD',(\nabla\psi)^{\oplus}\bigr\rangle_{P}.

By the uniqueness in Product Fields and the Projection onto One-Particle Tangent Fields §projection, ζ=ΠP(aD+bD′)\zeta=\Pi_{P}(aD+bD'). So ΠP\Pi_{P} is linear.

Step 5 (Contraction). Let D∈L2(P;RdN)D\in L^{2}(P;\mathbb{R}^{dN}) and a=N∥ΠP(D)∥μ≥0a=\sqrt{N}\lVert\Pi_{P}(D)\rVert_{\mu}\ge0, so that a2=N∥ΠP(D)∥μ2a^{2}=N\lVert\Pi_{P}(D)\rVert_{\mu}^{2} and, by Step 1, ∥ΠP(D)⊕∥P=a\lVert\Pi_{P}(D)^{\oplus}\rVert_{P}=a. Claim 1 with g=ΠP(D)∈Tμg=\Pi_{P}(D)\in T_{\mu} and The Cauchy-Schwarz Inequality in a Real Inner Product Space give

a2=N⟨ΠP(D),ΠP(D)⟩μ=⟨D,ΠP(D)⊕⟩P≤∥D∥P a.a^{2}=N\langle\Pi_{P}(D),\Pi_{P}(D)\rangle_{\mu}=\bigl\langle D,\Pi_{P}(D)^{\oplus}\bigr\rangle_{P}\le\lVert D\rVert_{P}\,a .

If a=0a=0, then N∥ΠP(D)∥μ2=0≤∥D∥P2N\lVert\Pi_{P}(D)\rVert_{\mu}^{2}=0\le\lVert D\rVert_{P}^{2}. If a>0a>0, then a≤∥D∥Pa\le\lVert D\rVert_{P}, since ∥D∥P<a\lVert D\rVert_{P}<a would give ∥D∥P a<a2\lVert D\rVert_{P}\,a<a^{2} by claim 10 of Elementary Order Arithmetic in an Ordered Field; hence ∥D∥P>0\lVert D\rVert_{P}>0 and, by claim 5 of Elementary Arithmetic in an Ordered Field applied to a≤∥D∥Pa\le\lVert D\rVert_{P} with the nonnegative factors aa and ∥D∥P\lVert D\rVert_{P}, a2≤∥D∥P a≤∥D∥P2a^{2}\le\lVert D\rVert_{P}\,a\le\lVert D\rVert_{P}^{2}. In both cases N∥ΠP(D)∥μ2≤∥D∥P2N\lVert\Pi_{P}(D)\rVert_{\mu}^{2}\le\lVert D\rVert_{P}^{2}, which with Step 4 is claim 2.

Step 6 (Claim 3). Let g∈Tμg\in T_{\mu} with Borel representative g~\tilde g, and let ψ∈Cc∞(Rd)\psi\in C_{c}^{\infty}(\mathbb{R}^{d}). The function f=g~⋅∇ψ:Rd→Rf=\tilde g\cdot\nabla\psi:\mathbb{R}^{d}\to\mathbb{R} is Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions and integrable with respect to μ\mu with ∫Rdf dμ=⟨g,∇ψ⟩μ\int_{\mathbb{R}^{d}}f\,d\mu=\langle g,\nabla\psi\rangle_{\mu}, by Square-Integrable Random Vectors: Coordinates, Operations, Almost Sure Equality and the Mean-Square Form §operations on the probability space (Rd,B(Rd),μ)(\mathbb{R}^{d},\mathcal{B}(\mathbb{R}^{d}),\mu) as in Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §fields. Since μ\mu is the measure APA_{P} of Existence and Uniqueness of Tensor Powers, and the Average of the Block Marginals §average (with q=dq=d) by The One-Particle Marginal of a Probability Measure on the Configuration Space §marginal, that clause shows that each f∘pkf\circ\mathfrak{p}_{k} is integrable with respect to PP and ∑k=1N∫RdNf∘pk dP=N∫Rdf dμ\sum_{k=1}^{N}\int_{\mathbb{R}^{dN}}f\circ\mathfrak{p}_{k}\,dP=N\int_{\mathbb{R}^{d}}f\,d\mu. For x∈RdNx\in\mathbb{R}^{dN}, Particle Blocks: Linearity, Splitting of Inner Products, Product Maps and Diagonal Shifts §inner-product (in RdN\mathbb{R}^{dN} with q=dq=d) and Particle Blocks: Linearity, Splitting of Inner Products, Product Maps and Diagonal Shifts §product-map give

g~⊕(x)⋅(∇ψ)⊕(x)=∑k=1Npk(g~⊕(x))⋅pk((∇ψ)⊕(x))=∑k=1Nf(pk(x)).\tilde g^{\oplus}(x)\cdot(\nabla\psi)^{\oplus}(x)=\sum_{k=1}^{N}\mathfrak{p}_{k}(\tilde g^{\oplus}(x))\cdot\mathfrak{p}_{k}((\nabla\psi)^{\oplus}(x))=\sum_{k=1}^{N}f(\mathfrak{p}_{k}(x)).

Integrating against PP and using Linearity of the Lebesgue Integral over a Finite Sum of Integrable Functions §linear (all coefficients 11),

⟨g⊕,(∇ψ)⊕⟩P=∑k=1N∫RdNf∘pk dP=N⟨g,∇ψ⟩μ.\bigl\langle g^{\oplus},(\nabla\psi)^{\oplus}\bigr\rangle_{P}=\sum_{k=1}^{N}\int_{\mathbb{R}^{dN}}f\circ\mathfrak{p}_{k}\,dP=N\langle g,\nabla\psi\rangle_{\mu}.

Thus g∈Tμg\in T_{\mu} satisfies ⟨g,∇ψ⟩μ=1N⟨g⊕,(∇ψ)⊕⟩P\langle g,\nabla\psi\rangle_{\mu}=\frac{1}{N}\langle g^{\oplus},(\nabla\psi)^{\oplus}\rangle_{P} for every ψ∈Cc∞(Rd)\psi\in C_{c}^{\infty}(\mathbb{R}^{d}), and the uniqueness in Product Fields and the Projection onto One-Particle Tangent Fields §projection (with D=g⊕D=g^{\oplus}) gives ΠP(g⊕)=g\Pi_{P}(g^{\oplus})=g, which is claim 3.

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