TheoremBase

The function is the composition of f with the continuous map u ↦ |u|^a, hence Borel measurable, and being nonnegative it is measurable into [0,∞].

Proof

The values ∣f(x)∣a|f(x)|^{a} are nonnegative by Properties of Real Powers (ii). The function ∣f∣a|f|^{a} is the composition of ff with u↦∣u∣au\mapsto|u|^{a}, which is continuous on R\mathbb{R} by Properties of Real Powers (viii). Since B(R)\mathcal{B}(\mathbb{R}) is the Borel σ\sigma-algebra of (R,dR)(\mathbb{R},d_{\mathbb{R}}) (Borel Sigma-Algebra of a Metric Space (ii)), this map is B(R)/B(R)\mathcal{B}(\mathbb{R})/\mathcal{B}(\mathbb{R})-measurable by Measurable Maps: Generators, Composition, Continuous Maps, Restrictions, and Criteria for Real- and [0,∞]-Valued Maps (iv), and so ∣f∣a|f|^{a} is measurable as a function into R\mathbb{R} by Measurable Maps: Generators, Composition, Continuous Maps, Restrictions, and Criteria for Real- and [0,∞]-Valued Maps (ii). Being nonnegative, it is then measurable as a function into [0,∞][0,\infty] by Measurable Maps: Generators, Composition, Continuous Maps, Restrictions, and Criteria for Real- and [0,∞]-Valued Maps (vii), that is, an element of M+(X,F)\mathcal{M}^{+}(X,\mathcal{F}).

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