Grid events. Let I be the set of pairs (i,iβ²) of integers with 0β€iβ€iβ²β€n and iβ²βiβ€m+2; it has at most (n+1)(m+3) elements, since i ranges over {0,β¦,n} and iβ²βi over {0,β¦,m+2}. For (i,iβ²)βI put
Ei,iβ²β={Ο:Β β£Piβ²β(Ο)βPiβ(Ο)β(iβ²βi)β£β₯x},
and let G be the complement of β(i,iβ²)βIβEi,iβ²β. Write H for the Ο-algebra generated by P0β,β¦,Pnβ. Each Piβ with 0β€iβ€n is H-measurable, so Οβ¦Piβ²β(Ο)βPiβ(Ο)β(iβ²βi) is H-measurable by claims 1 and 2 of Arithmetic, Absolute Values, and Pointwise Limits of Measurable Real-Valued Functions (constants, sums and scalar multiples), its absolute value is H-measurable by Sequentially Continuous Functions of Measurable Euclidean Maps are Measurable (the absolute value being continuous), and Ei,iβ²β, the preimage of [x,β), belongs to H; hence so does G, the complement of a finite union. If i=iβ² then Ei,iβ²β=β
because x>0. If i<iβ², the increment Piβ²ββPiβ has the Poisson distribution with parameter iβ²βi by condition 3 of Stochastic Process, Independent Increments, and Inhomogeneous Poisson Process (the mean function of a rate-1 process being Ξ(t)=t), so by claim 3 of Series Formula, Exponential Moments, and Chernoff Tail Bounds for the Poisson Distribution, with ΞΌ=iβ²βiβ€m+2 and its monotonicity assertion, P(Ei,iβ²β)β€2exp(βΟm+2β(x)). By countable subadditivity (claim 4 of Basic Properties of a Measure, applied to an enumeration of the finite family (Ei,iβ²β)(i,iβ²)βIβ padded with empty sets), P(Ξ©βG)β€β(i,iβ²)βIβP(Ei,iβ²β)β€2(n+1)(m+3)exp(βΟm+2β(x)), every term being at most 2exp(βΟm+2β(x)). (Only pairs with iβ²βiβ€m+1 are used below, so the constant could be sharpened slightly; we keep the simpler form.)
From grid windows to all windows. Fix ΟβG and real uβ€uβ² with 0β€uβ€uβ²β€n and uβ²βuβ€m; write P for the counting path P(Ο), which is nondecreasing by condition 2 of Counting Path and Its Jump Times. By Existence and Uniqueness of the Integer Part of a Real Number let βyβ denote the integer part of a real y, so yβ1<βyββ€y, and let βyβ be βyβ if y=βyβ and βyβ+1 otherwise, the least integer β₯y, so yβ€βyβ<y+1.
Upper bound. Put i=βuβ and iβ²=βuβ²β. Then iβ₯0 (as uβ₯0 and i is the largest integer β€u, while 0β€u), iβ€uβ€uβ²β€iβ², and iβ²β€n (as n is an integer β₯uβ²). Moreover iβ²βi<(uβ²+1)β(uβ1)=uβ²βu+2β€m+2, so (i,iβ²)βI and Οβ/Ei,iβ²β. By monotonicity of the path,
Puβ²ββPuββ€Piβ²ββPiβ<(iβ²βi)+x<(uβ²βu)+2+x.
Lower bound. Put j=βuβ and jβ²=βuβ²β, so uβ€j<u+1 and uβ²β1<jβ²β€uβ², both integers in [0,n]. If jβ€jβ², then jβ²βjβ€uβ²βuβ€m, so (j,jβ²)βI and Οβ/Ej,jβ²β; by monotonicity,
Puβ²ββPuββ₯Pjβ²ββPjβ>(jβ²βj)βx>(uβ²βu)β2βx.
If j>jβ², then no integer lies in [u,uβ²], which forces uβ²βu<1 (otherwise the integer βuβ+1 would satisfy u<βuβ+1β€u+1β€uβ²); hence Puβ²ββPuββ₯0>(uβ²βu)β1β₯(uβ²βu)β2βx.
Combining the two bounds, β£Puβ²ββPuββ(uβ²βu)β£β€x+2 for every window with 0β€uβ€uβ²β€n and uβ²βuβ€m, as claimed.