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Proof of The Bounded Lipschitz Vector Fields are Dense in the Square-Integrable Vector Fields Against a Probability Measure

lemmalem:lipschitz-fields-dense-l2-euclidean-2026a
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· 9,227 chars · 30 deps · depth 26 Reason: Phase B2b: proof by truncation where the norm is large, uniform approximation of each component by a simple function, and replacement of each indicator by a Lipschitz function agreeing with it off a set of small measure.

The field is first truncated where its norm is large, by dominated convergence; each component of the truncation is then uniformly approximated by a simple function, and each indicator occurring in it is replaced by a Lipschitz function agreeing with it off a set of small measure.

Proof

Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. By Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §l2mu the space L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) is a real Hilbert space with norm μ\lVert\cdot\rVert_{\mu} given by ημ2=Rdη2dμ\lVert\eta\rVert_{\mu}^{2}=\int_{\mathbb{R}^{d}}\lVert\eta\rVert^{2}\,d\mu, and a class is denoted by the same symbol as a representative of it; the triangle inequality η+ημημ+ημ\lVert\eta+\eta'\rVert_{\mu}\le\lVert\eta\rVert_{\mu}+\lVert\eta'\rVert_{\mu} is claim 1 of The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity. Let ι\iota denote the canonical map from N\mathbb{N} to R\mathbb{R}, positive by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. Since μP(Rd)\mu\in\mathcal{P}(\mathbb{R}^{d}) it is a Borel measure on (Rd,dE)(\mathbb{R}^{d},d_{E}) with μ(Rd)=1\mu(\mathbb{R}^{d})=1, by Probability Measures on Euclidean Space and Random Vectors: Standing Notation §measures, so Inner and Outer Regularity of a Finite Borel Measure on a Metric Space, and Lipschitz Approximation of Indicators applies to it. For AB(Rd)A\in\mathcal{B}(\mathbb{R}^{d}), 1A\mathbf{1}_{A} is its indicator, and Rd1Adμ=μ(A)\int_{\mathbb{R}^{d}}\mathbf{1}_{A}\,d\mu=\mu(A) by that lemma.

Fix a Borel representative of ξ\xi, again written ξ\xi, so Rdξ2dμ<\int_{\mathbb{R}^{d}}\lVert\xi\rVert^{2}\,d\mu<\infty. Its components ξ1,,ξd\xi_{1},\dots,\xi_{d} are Borel by claim 2 of The Borel Sigma-Algebra of a Euclidean Space as a Product, and Measurability of Projections, Sequentially Continuous Maps, and Open and Closed Sets, and v2=i=1dvi2\lVert v\rVert^{2}=\sum_{i=1}^{d}v_{i}^{2} for vRdv\in\mathbb{R}^{d} by claim 1 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n.

Step 1 (Truncation). For KNK\in\mathbb{N} let AK={xRd:ξ(x)ι(K)}A_{K}=\{x\in\mathbb{R}^{d}:\lVert\xi(x)\rVert\le\iota(K)\}, a member of B(Rd)\mathcal{B}(\mathbb{R}^{d}) because xξ(x)2x\mapsto\lVert\xi(x)\rVert^{2} is Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions and AKA_{K} is the preimage of a ray under it, by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field. Let ξK:RdRd\xi^{K}:\mathbb{R}^{d}\to\mathbb{R}^{d} agree with ξ\xi on AKA_{K} and vanish off AKA_{K}; it is Borel, since for BB(Rd)B\in\mathcal{B}(\mathbb{R}^{d}) its preimage is (AKξ1(B))(CKEB)(A_{K}\cap\xi^{-1}(B))\cup(C_{K}\cap E_{B}) with CK=RdAKC_{K}=\mathbb{R}^{d}\setminus A_{K} and EB=RdE_{B}=\mathbb{R}^{d} or \varnothing according as 0RdB0_{\mathbb{R}^{d}}\in B or not, and it satisfies ξK(x)ι(K)\lVert\xi^{K}(x)\rVert\le\iota(K) for every xx.

The functions fK=ξξK2f_{K}=\lVert\xi-\xi^{K}\rVert^{2} are Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, satisfy 0fKξ20\le f_{K}\le\lVert\xi\rVert^{2} (they vanish on AKA_{K} and equal ξ2\lVert\xi\rVert^{2} off it), and converge pointwise to 00: given xx, the real number ξ(x)\lVert\xi(x)\rVert satisfies ξ(x)<ι(K)\lVert\xi(x)\rVert<\iota(K) for some KNK\in\mathbb{N} by claim 1 of The Archimedean Property of the Real Numbers, and then xAKx\in A_{K'} and fK(x)=0f_{K'}(x)=0 for every KKK'\ge K, by claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. Since ξ2\lVert\xi\rVert^{2} is integrable with respect to μ\mu, claim 7 of The Lebesgue Integral and Null Sets: Almost-Everywhere Comparison, Markov's Inequality, and Dominated Convergence Almost Everywhere gives that (RdfKdμ)KN\bigl(\int_{\mathbb{R}^{d}}f_{K}\,d\mu\bigr)_{K\in\mathbb{N}} converges to 00, that is, ξξKμ20\lVert\xi-\xi^{K}\rVert_{\mu}^{2}\to0.

Fix the positive real number ε\varepsilon first. Choose KNK\in\mathbb{N} with ξξKμε2\lVert\xi-\xi^{K}\rVert_{\mu}\le\tfrac{\varepsilon}{2}, which is possible by the previous paragraph together with Existence and Uniqueness of the Nonnegative Square Root and claim 1 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field. Write M=ι(K)M=\iota(K).

Step 2 (Uniform approximation of a bounded component by a simple function). Let i[d]i\in[d] and let δ\delta be a positive real number. The function ξiK+M\xi^{K}_{i}+M is Borel and satisfies 0ξiK(x)+M2M0\le\xi^{K}_{i}(x)+M\le2M for every xx, by claim 4 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n and claim 3 of Properties of the Absolute Value in an Ordered Field. By Approximation of Measurable Functions by Simple Functions §bounded there is a sequence (sm)mN(s_{m})_{m\in\mathbb{N}} of nonnegative simple functions on (Rd,B(Rd))(\mathbb{R}^{d},\mathcal{B}(\mathbb{R}^{d})) with 0(ξiK(x)+M)sm(x)(12)m0\le(\xi^{K}_{i}(x)+M)-s_{m}(x)\le(\tfrac{1}{2})^{m} for every xRdx\in\mathbb{R}^{d} and every mNm\in\mathbb{N}. Since ((12)m)mN\bigl((\tfrac{1}{2})^{m}\bigr)_{m\in\mathbb{N}} converges to 00 by claim 4 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series, there is mNm\in\mathbb{N} with (12)mδ(\tfrac{1}{2})^{m}\le\delta; put s=sms=s_{m}, so that 0(ξiK(x)+M)s(x)δ0\le(\xi^{K}_{i}(x)+M)-s(x)\le\delta for every xx. The function σi=sM\sigma_{i}=s-M is again simple, having finite range and being measurable by claim 2 of Arithmetic, Absolute Values, and Pointwise Limits of Measurable Real-Valued Functions, and

ξiK(x)σi(x)δfor every xRd.|\xi^{K}_{i}(x)-\sigma_{i}(x)|\le\delta\qquad\text{for every }x\in\mathbb{R}^{d}.

Let c1,,crc_{1},\dots,c_{r} be the distinct values of σi\sigma_{i} and Aj=σi1({cj})B(Rd)A_{j}=\sigma_{i}^{-1}(\{c_{j}\})\in\mathcal{B}(\mathbb{R}^{d}), so that σi=j=1rcj1Aj\sigma_{i}=\sum_{j=1}^{r}c_{j}\mathbf{1}_{A_{j}}.

Step 3 (Replacing the indicators by Lipschitz functions). Let δ\delta' be a positive real number. By Inner and Outer Regularity of a Finite Borel Measure on a Metric Space, and Lipschitz Approximation of Indicators §lipschitz, applied to μ\mu and to each AjA_{j} with the positive real number δ\delta', there are maps hj:RdRh_{j}:\mathbb{R}^{d}\to\mathbb{R}, each Lipschitz with a constant and with values in [0,1][0,1], and sets NjB(Rd)N_{j}\in\mathcal{B}(\mathbb{R}^{d}) with μ(Nj)δ\mu(N_{j})\le\delta', such that hj=1Ajh_{j}=\mathbf{1}_{A_{j}} off NjN_{j}. Put

ζi=j=1rcjhj,Ni=j=1rNj.\zeta_{i}=\sum_{j=1}^{r}c_{j}h_{j},\qquad N^{i}=\bigcup_{j=1}^{r}N_{j}.

Write Ci=j=1rcjC_{i}=\sum_{j=1}^{r}|c_{j}| and let LjL_{j} be a Lipschitz constant for hjh_{j}. Then ζi\zeta_{i} is Lipschitz with constant j=1rcjLj\sum_{j=1}^{r}|c_{j}|L_{j}: by Comparison and Absolute Value Bounds for Finite Sums of Real Numbers, claim 4 of Properties of the Absolute Value in an Ordered Field, claim 5 of Elementary Arithmetic in an Ordered Field applied to hj(x)hj(y)LjdE(x,y)|h_{j}(x)-h_{j}(y)|\le L_{j}\,d_{E}(x,y) with the nonnegative factor cj|c_{j}|, and claims 2 and 3 of Properties of Finite Sums,

ζi(x)ζi(y)j=1rcjhj(x)hj(y)(j=1rcjLj)dE(x,y).|\zeta_{i}(x)-\zeta_{i}(y)|\le\sum_{j=1}^{r}|c_{j}|\,|h_{j}(x)-h_{j}(y)|\le\Bigl(\sum_{j=1}^{r}|c_{j}|L_{j}\Bigr)d_{E}(x,y).

Likewise ζi(x)j=1rcjhj(x)Ci|\zeta_{i}(x)|\le\sum_{j=1}^{r}|c_{j}|\,h_{j}(x)\le C_{i} for every xx, since 0hj10\le h_{j}\le1, so ζi\zeta_{i} is bounded by CiC_{i}; and ζi=σi\zeta_{i}=\sigma_{i} on RdNi\mathbb{R}^{d}\setminus N^{i}. Moreover μ(Ni)rδ\mu(N^{i})\le r\delta' by claim 4 of Basic Properties of a Measure, applied to the sequence whose first rr terms are N1,,NrN_{1},\dots,N_{r} and whose remaining terms are \varnothing, and ζiσi2Ci|\zeta_{i}-\sigma_{i}|\le2C_{i} everywhere.

Step 4 (Assembly). Apply Steps 2 and 3 for each i[d]i\in[d], with δ\delta and δ\delta' still to be fixed, and let ζ:RdRd\zeta:\mathbb{R}^{d}\to\mathbb{R}^{d} be the map with components ζ1,,ζd\zeta_{1},\dots,\zeta_{d}, which exists by claim 2 of Euclidean Points as Tuples of Real Numbers. It is bounded, by (i=1dCi2)1/2\bigl(\sum_{i=1}^{d}C_{i}^{2}\bigr)^{1/2}, and Lipschitz: if LiL_{i} is a Lipschitz constant for ζi\zeta_{i} then, by claim 1 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n,

ζ(x)ζ(y)2=i=1d(ζi(x)ζi(y))2(i=1dLi2)dE(x,y)2,\lVert\zeta(x)-\zeta(y)\rVert^{2}=\sum_{i=1}^{d}\bigl(\zeta_{i}(x)-\zeta_{i}(y)\bigr)^{2}\le\Bigl(\sum_{i=1}^{d}L_{i}^{2}\Bigr)d_{E}(x,y)^{2},

so ζ\zeta is Lipschitz with constant (iLi2)1/2\bigl(\sum_{i}L_{i}^{2}\bigr)^{1/2}. Hence ζ\zeta is bounded Lipschitz in the sense of the statement, and its class lies in L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}).

By claim 1 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n and claim 1 of Linearity and Monotonicity of the Lebesgue Integral, the integrands being nonnegative,

ξKζμ2=i=1dRd(ξiKζi)2dμ.\lVert\xi^{K}-\zeta\rVert_{\mu}^{2}=\sum_{i=1}^{d}\int_{\mathbb{R}^{d}}(\xi^{K}_{i}-\zeta_{i})^{2}\,d\mu .

For each ii, split the integrand: off NiN^{i} one has ζi=σi\zeta_{i}=\sigma_{i} and hence ξiKζiδ|\xi^{K}_{i}-\zeta_{i}|\le\delta by Step 2, while on NiN^{i} one has ξiKζiM+Ci|\xi^{K}_{i}-\zeta_{i}|\le M+C_{i}. Therefore, by claim 1 of Linearity and Monotonicity of the Lebesgue Integral and The Integral of an Indicator Function is the Measure of the Set,

Rd(ξiKζi)2dμδ2+(M+Ci)2μ(Ni)δ2+(M+Ci)2rδ.\int_{\mathbb{R}^{d}}(\xi^{K}_{i}-\zeta_{i})^{2}\,d\mu\le\delta^{2}+(M+C_{i})^{2}\,\mu(N^{i})\le\delta^{2}+(M+C_{i})^{2}r\,\delta' .

Now fix the order of choice: having fixed ε\varepsilon and then KK (hence MM), choose δ\delta positive with dδ2ε28d\,\delta^{2}\le\tfrac{\varepsilon^{2}}{8}; this determines, through Step 2, the simple functions σi\sigma_{i}, hence the numbers rr and CiC_{i}; then choose δ\delta' positive with i=1d(M+Ci)2rδε28\sum_{i=1}^{d}(M+C_{i})^{2}r\,\delta'\le\tfrac{\varepsilon^{2}}{8}. Summing over ii gives ξKζμ2ε24\lVert\xi^{K}-\zeta\rVert_{\mu}^{2}\le\tfrac{\varepsilon^{2}}{4}, so ξKζμε2\lVert\xi^{K}-\zeta\rVert_{\mu}\le\tfrac{\varepsilon}{2} by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field.

Finally, by the triangle inequality,

\lVert\xi-\zeta\rVert_{\mu}\le\lVert\xi-\xi^{K}\rVert_{\mu}+\lVert\xi^{K}-\zeta\rVert_{\mu}\le\tfrac{\varepsilon}{2}+\tfrac{\varepsilon}{2}=\varepsilon ,$$ which proves claim 1.
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