Proof of The Bounded Lipschitz Vector Fields are Dense in the Square-Integrable Vector Fields Against a Probability Measure
lemmalem:lipschitz-fields-dense-l2-euclidean-2026aThe field is first truncated where its norm is large, by dominated convergence; each component of the truncation is then uniformly approximated by a simple function, and each indicator occurring in it is replaced by a Lipschitz function agreeing with it off a set of small measure.
Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. By Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §l2mu the space is a real Hilbert space with norm given by , and a class is denoted by the same symbol as a representative of it; the triangle inequality is claim 1 of The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity. Let denote the canonical map from to , positive by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. Since it is a Borel measure on with , by Probability Measures on Euclidean Space and Random Vectors: Standing Notation §measures, so Inner and Outer Regularity of a Finite Borel Measure on a Metric Space, and Lipschitz Approximation of Indicators applies to it. For , is its indicator, and by that lemma.
Fix a Borel representative of , again written , so . Its components are Borel by claim 2 of The Borel Sigma-Algebra of a Euclidean Space as a Product, and Measurability of Projections, Sequentially Continuous Maps, and Open and Closed Sets, and for by claim 1 of Elementary Properties of the Euclidean Norm on .
Step 1 (Truncation). For let , a member of because is Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions and is the preimage of a ray under it, by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field. Let agree with on and vanish off ; it is Borel, since for its preimage is with and or according as or not, and it satisfies for every .
The functions are Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, satisfy (they vanish on and equal off it), and converge pointwise to : given , the real number satisfies for some by claim 1 of The Archimedean Property of the Real Numbers, and then and for every , by claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. Since is integrable with respect to , claim 7 of The Lebesgue Integral and Null Sets: Almost-Everywhere Comparison, Markov's Inequality, and Dominated Convergence Almost Everywhere gives that converges to , that is, .
Fix the positive real number first. Choose with , which is possible by the previous paragraph together with Existence and Uniqueness of the Nonnegative Square Root and claim 1 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field. Write .
Step 2 (Uniform approximation of a bounded component by a simple function). Let and let be a positive real number. The function is Borel and satisfies for every , by claim 4 of Elementary Properties of the Euclidean Norm on and claim 3 of Properties of the Absolute Value in an Ordered Field. By Approximation of Measurable Functions by Simple Functions §bounded there is a sequence of nonnegative simple functions on with for every and every . Since converges to by claim 4 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series, there is with ; put , so that for every . The function is again simple, having finite range and being measurable by claim 2 of Arithmetic, Absolute Values, and Pointwise Limits of Measurable Real-Valued Functions, and
Let be the distinct values of and , so that .
Step 3 (Replacing the indicators by Lipschitz functions). Let be a positive real number. By Inner and Outer Regularity of a Finite Borel Measure on a Metric Space, and Lipschitz Approximation of Indicators §lipschitz, applied to and to each with the positive real number , there are maps , each Lipschitz with a constant and with values in , and sets with , such that off . Put
Write and let be a Lipschitz constant for . Then is Lipschitz with constant : by Comparison and Absolute Value Bounds for Finite Sums of Real Numbers, claim 4 of Properties of the Absolute Value in an Ordered Field, claim 5 of Elementary Arithmetic in an Ordered Field applied to with the nonnegative factor , and claims 2 and 3 of Properties of Finite Sums,
Likewise for every , since , so is bounded by ; and on . Moreover by claim 4 of Basic Properties of a Measure, applied to the sequence whose first terms are and whose remaining terms are , and everywhere.
Step 4 (Assembly). Apply Steps 2 and 3 for each , with and still to be fixed, and let be the map with components , which exists by claim 2 of Euclidean Points as Tuples of Real Numbers. It is bounded, by , and Lipschitz: if is a Lipschitz constant for then, by claim 1 of Elementary Properties of the Euclidean Norm on ,
so is Lipschitz with constant . Hence is bounded Lipschitz in the sense of the statement, and its class lies in .
By claim 1 of Elementary Properties of the Euclidean Norm on and claim 1 of Linearity and Monotonicity of the Lebesgue Integral, the integrands being nonnegative,
For each , split the integrand: off one has and hence by Step 2, while on one has . Therefore, by claim 1 of Linearity and Monotonicity of the Lebesgue Integral and The Integral of an Indicator Function is the Measure of the Set,
Now fix the order of choice: having fixed and then (hence ), choose positive with ; this determines, through Step 2, the simple functions , hence the numbers and ; then choose positive with . Summing over gives , so by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field.
Finally, by the triangle inequality,
\lVert\xi-\zeta\rVert_{\mu}\le\lVert\xi-\xi^{K}\rVert_{\mu}+\lVert\xi^{K}-\zeta\rVert_{\mu}\le\tfrac{\varepsilon}{2}+\tfrac{\varepsilon}{2}=\varepsilon ,$$ which proves claim 1.Loading…
Prerequisites
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