Let x,yβE. We use the notation and claims of Elementary Identities in a Real Inner Product Space.
If y=0Eβ, then β¨x,yβ©=0 and β£yβ£=0 by Elementary Identities in a Real Inner Product Space (ii), so both sides of the asserted inequality equal 0 (using β£0β£=0, claim 1 of Properties of the Absolute Value in an Ordered Field), and there is nothing to prove.
Suppose yξ =0Eβ. Then 0<β£yβ£ by Elementary Identities in a Real Inner Product Space (iii), hence 0<β£yβ£2 by claim 5 of Elementary Order Arithmetic in an Ordered Field, and β£yβ£2 has a multiplicative inverse. Put t=β¨x,yβ©(β£yβ£2)β1βR. By Elementary Identities in a Real Inner Product Space (v), Elementary Identities in a Real Inner Product Space (i) and Elementary Identities in a Real Inner Product Space (iv),
0β€β£xβtyβ£2=β£xβ£2β2β¨x,tyβ©+β£tyβ£2=β£xβ£2β2tβ¨x,yβ©+t2β£yβ£2,
the first inequality being condition (d) of Real Inner Product Spaces (i), since β£xβtyβ£2=β¨xβty,xβtyβ©. With the chosen t we have tβ¨x,yβ©=β¨x,yβ©2(β£yβ£2)β1 and t2β£yβ£2=β¨x,yβ©2(β£yβ£2)β1, so the display reads
0β€β£xβ£2ββ¨x,yβ©2(β£yβ£2)β1.
Multiplying by the positive number β£yβ£2 (claim 5 of Elementary Arithmetic in an Ordered Field) and rearranging by the translation rule (claim 3 of Elementary Arithmetic in an Ordered Field) gives β¨x,yβ©2β€β£xβ£2β£yβ£2=(β£xβ£β£yβ£)2. Now β£β¨x,yβ©β£2=β¨x,yβ©2 because β£β¨x,yβ©β£ equals β¨x,yβ© or ββ¨x,yβ© (claim 1 of Properties of the Absolute Value in an Ordered Field), and both β£β¨x,yβ©β£ and β£xβ£β£yβ£ are nonnegative (the same claim; and 0=β£xβ£β
0β€β£xβ£β£yβ£ by claim 5 of Elementary Arithmetic in an Ordered Field). Therefore β£β¨x,yβ©β£β€β£xβ£β£yβ£ by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field.