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Comparison and Uniqueness for Free-Energy-Penalised Viscosity Solutions of the Discounted HJB Equation with Free Langevin Noise in a Wall

Under the structure condition on the Hamiltonian, a bounded weak-star upper semicontinuous penalised subsolution lies below a bounded weak-star lower semicontinuous penalised supersolution on the domain of the wall-confined free energy; solutions are unique there.

Statement

In the setting of The Discounted Hamilton-Jacobi-Bellman Equation with Free Langevin Noise in a Wall on Noncommutative Laws: Standing Notation, consider the equation (E)(\mathrm{E}) of The Discounted Hamilton-Jacobi-Bellman Equation with Free Langevin Noise in a Wall on Noncommutative Laws §score-form, let D\mathcal{D} be the domain of the wall-confined free energy as in The Discounted Hamilton-Jacobi-Bellman Equation with Free Langevin Noise in a Wall on Noncommutative Laws: Standing Notation §free-energy, and assume that the Hamiltonian H\mathcal{H} of The Discounted Hamilton-Jacobi-Bellman Equation with Free Langevin Noise in a Wall on Noncommutative Laws: Standing Notation §hamiltonian satisfies the structure condition.

1. (Comparison) Let u,v:Σd2→Ru,v:\Sigma^{2}_{d}\to\mathbb{R} be bounded; let uu be weak-star upper semicontinuous on bounded laws and a free-energy-penalised viscosity subsolution of (E)(\mathrm{E}), and let vv be weak-star lower semicontinuous on bounded laws and a free-energy-penalised viscosity supersolution of (E)(\mathrm{E}). Then u(κd(μ))≤v(κd(μ))u(\kappa_{d}(\mu))\le v(\kappa_{d}(\mu)) for every μ∈D\mu\in\mathcal{D}.

2. (Uniqueness) Let u,v:Σd2→Ru,v:\Sigma^{2}_{d}\to\mathbb{R} be bounded, weak-star continuous on bounded laws, and free-energy-penalised viscosity solutions of (E)(\mathrm{E}). Then u(κd(μ))=v(κd(μ))u(\kappa_{d}(\mu))=v(\kappa_{d}(\mu)) for every μ∈D\mu\in\mathcal{D}.

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