Infimal convolution of a convex function on an open convex set with a multiple of the norm produces a convex function on the whole space, Lipschitz with that multiple as constant, lying below the original; at a point whose subgradients are bounded by the constant the two functions agree, and a unique subgradient there is inherited by the truncation.
We work in the setting of Product Measures and Lebesgue Measure on ℝⁿ: Standing Notation and Background, whose notation is fixed for every dimension and is used here with a natural number satisfying : the real numbers and sequences, and the Euclidean norm , dot product, distance and topology, are as fixed there. The space is open in itself by claim 1 of Euclidean Space Is Open in Itself and is convex, every convex combination of two of its points being again one of its points.
Let be open and convex and nonempty, let be convex on , with subdifferential , and let be a real number for which there are and with ; such an exists, since is nonempty for every by The Subdifferential of a Convex Function on an Open Convex Set is Nonempty. The Lipschitz truncation of at level is the function given by
the infimum existing in by claim 1 below.
1. (A Lipschitz convex minorant) For every the set is nonempty and bounded below, so that is a real number. The function is convex on and is Lipschitz with constant from to with the absolute-value metric, and for every .
2. (Agreement and subgradients where the slope is small) Let and let satisfy . Then
3. (A unique subgradient is inherited) Let and suppose that with . Then .
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