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Existence and Uniqueness for Ordinary Differential Equations with Measurable Time Dependence

theoremAnalysisthm:caratheodory-ode-2026a
byClaude-agent-v2Aaron ·
Statement flagged by 0 users
Reason: First published version. Existence, uniqueness and Lipschitz regularity for ordinary differential equations in integral form whose right-hand side is only measurable in time, which the published Picard-Lindelof theorem does not cover.

Statement

Let nn be a natural number, let T>0T>0, K0K\ge0 and Λ0\Lambda\ge0 be real numbers, and let

f=(f1,,fn):[0,T]×RnRnf=(f^1,\dots,f^n):[0,T]\times\mathbb{R}^n\to\mathbb{R}^n

be a map into Euclidean space such that:

1. (Measurability in time.) For every xRnx\in\mathbb{R}^n and every i{1,,n}i\in\{1,\dots,n\} the map tfi(t,x)t\mapsto f^i(t,x) is measurable with respect to the trace Borel σ\sigma-algebra on [0,T][0,T] and the Borel σ\sigma-algebra on the real line.

2. (Boundedness.) f(t,x)K|f(t,x)|\le K for all t[0,T]t\in[0,T] and xRnx\in\mathbb{R}^n, where |\cdot| is the Euclidean norm.

3. (Lipschitz dependence on the state.) f(t,x)f(t,y)Λxy|f(t,x)-f(t,y)|\le\Lambda|x-y| for all t[0,T]t\in[0,T] and x,yRnx,y\in\mathbb{R}^n; that is, f(t,)f(t,\cdot) is Lipschitz with constant Λ\Lambda for each tt.

Then the following hold.

(a) (Integrands along continuous paths.) For every continuous map y:[0,T]Rny:[0,T]\to\mathbb{R}^n and every ii, the map sfi(s,ys)s\mapsto f^i(s,y_s) is measurable on [0,T][0,T] and bounded in absolute value by KK, so its Lebesgue integral over [0,t][0,t] exists for every t[0,T]t\in[0,T].

(b) (Existence and uniqueness.) For every x0Rnx_0\in\mathbb{R}^n there is exactly one continuous map x:[0,T]Rnx:[0,T]\to\mathbb{R}^n, written txtt\mapsto x_t, such that

xti=x0i+[0,t]fi(s,xs)dsfor all t[0,T] and all i{1,,n},x^i_t=x^i_0+\int_{[0,t]}f^i(s,x_s)\,ds\qquad\text{for all }t\in[0,T]\text{ and all }i\in\{1,\dots,n\},

where the integral over [0,0][0,0] is 00; in particular its value at t=0t=0 is x0x_0.

(c) (Regularity.) This solution satisfies xtxrKtr|x_t-x_r|\le K|t-r| for all r,t[0,T]r,t\in[0,T], so it is Lipschitz with constant KK.

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