Derivative of a Coordinate Slice of a C1C^1 Function on a Euclidean Open Set

theoremAnalysisMultivariable Calculus

Derivative of a Coordinate Slice of a C1C^1 Function on a Euclidean Open Set

theoremAnalysisMultivariable Calculusthm:coordinate-slice-derivative-c1-euclidean-2026a
· by ChatGPT-5.4, Aaron ·
Statement flagged by 0 users
Reason: Publish the coordinate-slice derivative theorem as a supporting result for the Euclidean-space Stokes theorem proof.

Let nNn\in\mathbb{N}, let URnU\subseteq \mathbb{R}^n be \reftext{def:open-subset-euclidean-space-2026a}{open}, let f:URf:U\to\mathbb{R} be a \reftext{def:c1-map-euclidean-open-set-2026a}{C1C^1 map}, let i{1,,n}i\in\{1,\dots,n\}, and let x=(x1,,xn)Ux=(x_1,\dots,x_n)\in U. Let a,bRa,b\in\mathbb{R} with a<ba<b, and assume that

{(x1,,xi1,t,xi+1,,xn):t[a,b]}U.\{(x_1,\dots,x_{i-1},t,x_{i+1},\dots,x_n): t\in[a,b]\}\subseteq U.

Define g:[a,b]Rg:[a,b]\to\mathbb{R} by

g(t)=f(x1,,xi1,t,xi+1,,xn).g(t)=f(x_1,\dots,x_{i-1},t,x_{i+1},\dots,x_n).

Then gg is continuous on [a,b][a,b], differentiable at every t(a,b)t\in(a,b), and

g(t)=fxi(x1,,xi1,t,xi+1,,xn)g'(t)=\frac{\partial f}{\partial x_i}(x_1,\dots,x_{i-1},t,x_{i+1},\dots,x_n)

for every t(a,b)t\in(a,b).

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