TheoremBase

Limit Superior of a Bounded Sequence of Real Numbers

Statement

Let (an)n∈N(a_{n})_{n\in\mathbb{N}} be a bounded sequence of real numbers, and for k∈Nk\in\mathbb{N} write

Ak={am  :  m∈N, m≥k}.A_{k}=\{a_{m}\;:\;m\in\mathbb{N},\ m\ge k\}.

Let M>0M>0 be a real number with ∣an∣≤M|a_{n}|\le M for every n∈Nn\in\mathbb{N}, as provided by the boundedness of the sequence, so that −M≤an≤M-M\le a_{n}\le M for every nn. Each AkA_{k} is nonempty, since ak∈Aka_{k}\in A_{k}, and is bounded above by MM, so it has a least upper bound by Least Upper Bound Property of the Real Numbers, unique by Uniqueness of the Supremum and of the Infimum; and the set {sup⁡Ak:k∈N}\{\sup A_{k}:k\in\mathbb{N}\} is nonempty and bounded below, so its infimum exists by Existence of the Infimum of a Nonempty Subset of R\mathbb{R} Bounded Below.

The limit superior of (an)n∈N(a_{n})_{n\in\mathbb{N}} is

lim sup⁡nan=inf⁡{sup⁡Ak  :  k∈N}.\limsup_{n}a_{n}=\inf\bigl\{\sup A_{k}\;:\;k\in\mathbb{N}\bigr\}.

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