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Bounded Open Domain in Euclidean Space

Standing hypotheses for a nonempty bounded open subset of Euclidean space: its closure is compact, and its boundary is the complement of the domain in the closure.

Statement

In the setting of Second-Order Equations on Euclidean Open Sets, this setting fixes a bounded open domain in Euclidean space together with the notation for its closure and its boundary.

Let nn be a natural number with n≥1n\ge1.

1. (The domain) Ω⊆Rn\Omega\subseteq\mathbb{R}^{n} is nonempty, open and bounded.

2. (Closure and compactness) We write Ω‾=cl⁡Rn(Ω)\overline{\Omega}=\operatorname{cl}_{\mathbb{R}^{n}}(\Omega). Then Ω⊆Ω‾\Omega\subseteq\overline{\Omega} by The Closure is the Smallest Closed Superset, so that Ω‾\overline{\Omega} is nonempty; moreover Ω‾\overline{\Omega} is bounded by The Closure of a Bounded Subset of a Metric Space is Bounded and compact by The Closure of a Bounded Subset of Rn\mathbb{R}^n is Compact.

3. (Boundary) We write ∂Ω=∂RnΩ\partial\Omega=\partial_{\mathbb{R}^{n}}\Omega. Since Ω\Omega is open, claim 4 of The Interior is the Largest Open Subset gives int⁡Rn(Ω)=Ω\operatorname{int}_{\mathbb{R}^{n}}(\Omega)=\Omega, so that by the definition of the boundary

∂Ω=Ω‾∖Ω.\partial\Omega=\overline{\Omega}\setminus\Omega .

In particular ∂Ω⊆Ω‾\partial\Omega\subseteq\overline{\Omega}, the sets Ω\Omega and ∂Ω\partial\Omega are disjoint, and Ω‾=Ω∪∂Ω\overline{\Omega}=\Omega\cup\partial\Omega.

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