TheoremBase

Measure, Measure Space, and Probability Measure

Defines a measure on a measurable space as a countably additive map from the measurable sets to [0,∞] vanishing on the empty set, a measure space, and finite, σ-finite and probability measures.

Statement

In the setting of Routine Facts Used Without Citation: Arithmetic, Maps, Predicativity and Indices, let (X,F)(X,\mathcal{F}) be a measurable space. Then X∈FX\in\mathcal{F} by σ-Algebra and Measurable Space (i), and ∅∈F\emptyset\in\mathcal{F} for the empty set ∅\emptyset, by Closure Properties of σ-Algebras, Intersections and Traces of σ-Algebras, and the Generated σ-Algebra (vi). Let ∞\infty, [0,∞][0,\infty] and << be as in The Extended Real Line, Its Order, and [0,∞] (i), The Extended Real Line, Its Order, and [0,∞] (ii) and The Extended Real Line, Its Order, and [0,∞] (iii); 1∈[0,∞]1\in[0,\infty] by Addition and Multiplication on [0,∞] (ii). For a sequence (am)(a_{m}) in [0,∞][0,\infty], ∑m∈Nam\sum_{m\in\mathbb{N}}a_{m} is its sum. For a sequence (Am)(A_{m}) in F\mathcal{F}, ⋃m∈NAm\bigcup_{m\in\mathbb{N}}A_{m} is the union of (Am)(A_{m}) as a family indexed by N\mathbb{N}, and ⋃m∈NAm∈F\bigcup_{m\in\mathbb{N}}A_{m}\in\mathcal{F} by σ-Algebra and Measurable Space (i); the sequence (Am)(A_{m}) is pairwise disjoint if Am∩Ak=∅A_{m}\cap A_{k}=\emptyset for all m,k∈Nm,k\in\mathbb{N} with m≠km\neq k, where ∩\cap is the intersection.

A measure on (X,F)(X,\mathcal{F}) is a map μ:F→[0,∞]\mu:\mathcal{F}\to[0,\infty] such that μ(∅)=0\mu(\emptyset)=0 and

μ(⋃m∈NAm)=∑m∈Nμ(Am)\mu\Bigl(\bigcup_{m\in\mathbb{N}}A_{m}\Bigr)=\sum_{m\in\mathbb{N}}\mu(A_{m})

for every pairwise disjoint sequence (Am)(A_{m}) in F\mathcal{F}, the right-hand side being the sum of the sequence m↦μ(Am)m\mapsto\mu(A_{m}) in [0,∞][0,\infty] (countable additivity).

A measure space is the tuple (X,F,μ)=⟨X,F,μ⟩(X,\mathcal{F},\mu)=\langle X,\mathcal{F},\mu\rangle of a measurable space (X,F)(X,\mathcal{F}) and a measure μ\mu on (X,F)(X,\mathcal{F}).

Let μ\mu be a measure on (X,F)(X,\mathcal{F}).

μ\mu is finite if μ(X)<∞\mu(X)<\infty.

μ\mu is σ\sigma-finite if there is a sequence (Xm)(X_{m}) in F\mathcal{F} with ⋃m∈NXm=X\bigcup_{m\in\mathbb{N}}X_{m}=X and μ(Xm)<∞\mu(X_{m})<\infty for every m∈Nm\in\mathbb{N}.

μ\mu is a probability measure if μ(X)=1\mu(X)=1.

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