Adopt the setting and notation of Clock-Reading Bound for the Aggregate Recursion: the Recursion up to a Time Depends Only on the Clocks Below the Consumed Levels (that of Existence, Uniqueness, Causality, and Measurability of the Open-Loop Aggregate Solution): natural numbers N≥1, l≥2, m≥1, a nonempty control set A⊆Rm in Euclidean space, real numbers B≥0 and T>0, a transition-rate family β with control set A and rate bound B, the aggregate lattice GN (a nonempty finite set), the transition labels c=(σ,γ) with vectors vc, a fixed control path a and a fixed point x0∈GN. Let R be a real number or +∞ with R>NBT, and let (Ω,F,P) be a probability space carrying a family P=(Pc), indexed by the transition labels, such that each Pc is a Poisson clock with horizon R and the family of σ-algebras σ(Puc:u≥0), indexed by the labels, is independent (for R=+∞ this says that P is a family of aggregate transition clocks; for finite R>NBT the copy clocks of The Copy Clocks Are Independent Poisson Clocks with Horizon R, and Every Record Is Almost Surely Conflict-Free for Them qualify, that lemma allowing any R≥NBT). For ω∈Ω run the aggregate recursion for the data (P(ω),a,x0), with recursion path Σt(ω), recursion consumed times Ctc(ω), recursion counters Ntc(ω) and recursion filtration (Ft)t∈[0,T] as in Clock-Reading Bound for the Aggregate Recursion: the Recursion up to a Time Depends Only on the Clocks Below the Consumed Levels, and let Ω0 be the event that the data (P(ω),a,x0) are conflict-free (an event by claim 4 of Existence, Uniqueness, Causality, and Measurability of the Open-Loop Aggregate Solution, applied with a one-point parameter space). Assume P(Ω0)=1.
For a label c=(σ,γ), u∈[0,T] and x∈GN put
gc(u,x)=Nxσβ(σ,γ,x,au)∈[0,NB],ϕc(x)={x+N1vcxif x+N1vc∈GN,otherwise,
and for u∈[0,T] and x=y in GN put qu(x,y)=∑c:ϕc(x)=ygc(u,x), which equals Nxσβ(σ,γ,x,au) if y=x+N1vc for the (then unique) label c=(σ,γ), and 0 if y−x is not of the form N1vc. Finally let Σˉt(ω)=Σt(ω) if Σt(ω)∈GN and Σˉt(ω)=x0 otherwise (so Σˉ=Σ on Ω0, where the recursion path stays in GN). Then:
1. (The recursion is a Poisson-clock jump system.) The data consisting of (Ω,F,P), T, Λ=NB, the state space E=GN, the clock labels A= the transition labels, the clocks Yc=Pc, the rate functions gc, the transition maps ϕc, the filtration (Ft), the event Ω0, the state process Xt=Σˉt and the consumed clock times Ttc=Ctc satisfy (D1)--(D4), (H1) and (H2) of Forward Equation for a Finite-State Jump System Driven by Poisson Clocks with the Fresh-Start Property; the counters of that lemma are the recursion counters Ntc.
2. (Forward equation.) Consequently, for every F:GN→R, all 0≤r≤t≤T and every D∈Fr,
E[(F(Σˉt)−F(Σˉr))1D]=E[1D∫[r,t]1Ω0c=(σ,γ)∑NΣˉuσβ(σ,γ,Σˉu,au)(F(Σˉu+N1vc)−F(Σˉu))du],
where F(Σˉu+N1vc) is read as F(Σˉu) when Σˉu+N1vc∈/GN (in which case Σˉuσ=0, so the term vanishes anyway); and for every r∈[0,T) and D∈Fr the family μuD(x)=P(D∩{Σˉu=x}) (u∈[r,T], x∈GN) is a solution of the forward equation on [r,T] for the rates q with rate bound l(l−1)NB.