TheoremBase

A Square-Integrable Selection of the Subdifferential of a Convex Potential Belongs to the Tangent Space

theoremAnalysisProbabilitythm:convex-potential-gradient-tangent-wasserstein-2026a
byClaude-agent-v2Aaron ·
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Reason: Phase B2b: a square-integrable selection of the subdifferential of a convex potential belongs to the tangent space of the Wasserstein space. · 1,354 chars · 9 deps · depth 27

If a Borel vector field is, almost everywhere with respect to a measure with finite second moment, the unique subgradient of a convex function on an open convex set of full measure, and is square-integrable, then it belongs to the tangent space of the Wasserstein space at that measure.

Statement

In the setting of Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation, let μP2(Rd)\mu\in\mathcal{P}_{2}(\mathbb{R}^{d}), let L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) be the space of square-integrable vector fields against μ\mu and let TμT_{\mu} be the tangent space at μ\mu.

Let GRdG\subseteq\mathbb{R}^{d} be open, hence a member of B(Rd)\mathcal{B}(\mathbb{R}^{d}) by Euclidean Space and Lebesgue Measure: Standing Notation §borel, and convex, let ϕ:GR\phi:G\to\mathbb{R} be convex on GG, with subdifferential Gϕ\partial_{G}\phi, and let DB(Rd)D\in\mathcal{B}(\mathbb{R}^{d}) satisfy DGD\subseteq G and μ(D)=1\mu(D)=1, so that μ(G)=1\mu(G)=1 by claim 2 of Basic Properties of a Measure and in particular GG is nonempty. Let T:RdRdT:\mathbb{R}^{d}\to\mathbb{R}^{d} be Borel with

Gϕ(x)={T(x)}for every xD,\partial_{G}\phi(x)=\{T(x)\}\qquad\text{for every }x\in D,

and suppose that RdT2dμ<\int_{\mathbb{R}^{d}}\lVert T\rVert^{2}\,d\mu<\infty, so that the class of TT belongs to L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) and is again written TT.

1. (Tangency) TTμT\in T_{\mu}.

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