Adopt the setting and notation of Existence, Uniqueness, Causality, and Measurability of the Open-Loop Aggregate Solution (and hence of Open-Loop Aggregate Solution Driven by Aggregate Transition Clocks): natural numbers N≥1, l≥2, m≥1, the control set A, real numbers B≥0 and T>0, the transition-rate family β with rate bound B, the aggregate lattice GN⊆Δl (with Δl the probability simplex), the transition labels c=(σ,γ) with vectors vc=δγ−δσ, clock families p=(pc) of counting paths with jump times τj(⋅), control paths a, and, for data (p,a,x0) with x0∈GN, the aggregate recursion with its times θk, points x(k), stopping index K and the quantities κkc, Cc,(k), λkc, hkc, Jk defined there (which we call the consumed levels, step consumed-time functions, next jump levels, hitting times and firing sets respectively), the notion of conflict-free data, and the recursion consumed times Ctrec,c (t∈[0,T]). Greatest lower bounds are as there (+∞ for the empty set), 1{⋅} is the indicator of a condition, and a real number u>0 is a jump time of a counting path q if q(u)>q(u−), where q(u−) is the least upper bound of {q(s):0≤s<u}, as in Counting Path and Its Jump Times. Fix data (p,a,x0) and run the recursion. A step k<K is called a tie if the firing set Jk has at least two elements.
1. (Consumed levels and first hitting times) For every label c=(σ,γ): the map t↦Ctrec,c is nondecreasing on [0,T] with ∣Ctrec,c−Csrec,c∣≤NB(t−s) for 0≤s≤t≤T, and C0rec,c=0; for every k<K, κkc≤κk+1c, Ctrec,c≤κk+1c for t∈[0,θk+1], and Ctrec,c<λkc for t∈[0,θk+1); and if k<K and c∈Jk, then x(k),σ>0, κk+1c=λkc, and
θk+1=hkc=inf{t∈[0,T]: Ctrec,c≥λkc},
the first time at which the recursion consumed time of c reaches the next jump level λkc.
2. (No ties implies conflict-free) If no step k<K is a tie, then x(k)∈GN for every k≤K, and the data (p,a,x0) are conflict-free.
3. (Point deletion) Let c0 be a label and u>0 a jump time of pc0, and let p−=(p−,c) be the family with p−,c=pc for c=c0 and p−,c0(t)=pc0(t)−1{t≥u} for t≥0. Then p−,c0 is a counting path, so p− is a clock family; run the recursion for the data (p−,a,x0) and mark its quantities by a minus sign. Suppose that for some step k<K one has c0∈Jk, λkc0=u, and Jk contains a label c′=c0 (so that k is a tie); put v=λkc′, a jump time of pc′=p−,c′. Then the recursion for p− performs the steps 0,…,k with θi−=θi, x−(i)=x(i) and κi−,c=κic for all i≤k and all c, and moreover θk+1−=θk+1, Ct−,rec,c=Ctrec,c for all c and t∈[0,θk+1],
θk+1=inf{t∈[0,T]: Ct−,rec,c′≥v},andu=Cθk+1−,rec,c0.