TheoremBase

Multi-Index of Length nn

Statement

Let n∈Nn\in\mathbb{N}. A multi-index of length nn is an element

α=(α1,…,αn)∈(N∪{0})n.\alpha=(\alpha_1,\dots,\alpha_n)\in(\mathbb{N}\cup\{0\})^n.

That is, a multi-index of length nn is an ordered nn-tuple of nonnegative integers. The zero multi-index of length nn is

0=(0,…,0).0=(0,\dots,0).

For each index i∈{1,…,n}i\in\{1,\dots,n\}, the iith standard basis multi-index is

ei=(0,…,0,1,0,…,0),e_i=(0,\dots,0,1,0,\dots,0),

with 11 in the iith position and 00 elsewhere. If

α=(α1,…,αn),β=(β1,…,βn)\alpha=(\alpha_1,\dots,\alpha_n),\qquad \beta=(\beta_1,\dots,\beta_n)

are multi-indices of length nn, we write

β≤α\beta\le \alpha

if and only if βi≤αi\beta_i\le \alpha_i for every i∈{1,…,n}i\in\{1,\dots,n\}. In that case the difference

α−β\alpha-\beta

is the multi-index of length nn defined componentwise by

α−β=(α1−β1,…,αn−βn).\alpha-\beta=(\alpha_1-\beta_1,\dots,\alpha_n-\beta_n).

In particular, if αi>0\alpha_i>0, then ei≤αe_i\le \alpha and

α−ei=(α1,…,αi−1,αi−1,αi+1,…,αn).\alpha-e_i=(\alpha_1,\dots,\alpha_{i-1},\alpha_i-1,\alpha_{i+1},\dots,\alpha_n).

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