TheoremBase

Lebesgue Measure on the Real Line: Existence, Lengths of Intervals and Uniqueness

Assuming dependent choice, Lebesgue outer measure is an outer measure, every Borel set is Carathéodory measurable, and Lebesgue measure is a sigma-finite measure on the Borel sets giving each interval its length; it is the only measure on the Borel sets giving each half-open interval its length.

Statement

In the setting of Routine Facts Used Without Citation: Arithmetic, Maps, Predicativity and Indices, let λ∗\lambda^{*} be the Lebesgue outer measure on R\mathbb{R}, let B(R)\mathcal{B}(\mathbb{R}) be the Borel σ\sigma-algebra of R\mathbb{R}, so that (R,B(R))(\mathbb{R},\mathcal{B}(\mathbb{R})) is a measurable space by Closure Properties of σ-Algebras, Intersections and Traces of σ-Algebras, and the Generated σ-Algebra (iii), and let λ\lambda be Lebesgue measure on R\mathbb{R}. Intervals are as in Intervals of the Real Line (ii).

For all a,b∈Ra,b\in\mathbb{R} with a≤ba\le b, the intervals (a,b)(a,b), [a,b][a,b], [a,b)[a,b) and (a,b](a,b] belong to B(R)\mathcal{B}(\mathbb{R}) by Intervals Are Borel, and Rays, Half-Open Intervals and Rational Intervals Generate the Borel Sigma-Algebra of the Real Line (ii), and

λ((a,b))=λ([a,b])=λ([a,b))=λ((a,b])=b−a.\lambda\bigl((a,b)\bigr)=\lambda\bigl([a,b]\bigr)=\lambda\bigl([a,b)\bigr)=\lambda\bigl((a,b]\bigr)=b-a.

Assume moreover that the axiom of dependent choice holds.

λ∗\lambda^{*} is an outer measure on R\mathbb{R}.

Every Borel subset of R\mathbb{R} is Carathéodory measurable for λ∗\lambda^{*}, which is an outer measure by (ii); that is, B(R)⊆M(λ∗)\mathcal{B}(\mathbb{R})\subseteq\mathcal{M}(\lambda^{*}), where M(λ∗)\mathcal{M}(\lambda^{*}) is the set of Carathéodory measurable sets for λ∗\lambda^{*}.

λ\lambda is a measure on (R,B(R))(\mathbb{R},\mathcal{B}(\mathbb{R})).

λ\lambda is σ\sigma-finite.

If ν\nu is a measure on (R,B(R))(\mathbb{R},\mathcal{B}(\mathbb{R})) with ν((a,b])=b−a\nu\bigl((a,b]\bigr)=b-a for all a,b∈Ra,b\in\mathbb{R} with a<ba<b, then ν(B)=λ(B)\nu(B)=\lambda(B) for every B∈B(R)B\in\mathcal{B}(\mathbb{R}), that is, ν=λ\nu=\lambda.

Proofs

Log in to submit a proof.

Loading...

Citations

Loading…

Dependencies

Loading…

Related

0 relations

Curated associations between results. These are editable and subjective — they do not replace the dependency graph, which is derived from the references in the text.

No relations recorded yet.

Comments

Log in to comment.

Loading…