TheoremBase

The Displacement Pairing of a Square-Integrable Vector Field Along a Coupling

The integral of a square-integrable vector field against the displacement of a coupling: it is well defined, bounded by the norm of the field times the square root of the cost, linear in the field, and reduces to an inner product along a displacement coupling.

Statement

In the setting of Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation, let μ,ν∈P2(Rd)\mu,\nu\in\mathcal{P}_{2}(\mathbb{R}^{d}) and let π∈Π(μ,ν)\pi\in\Pi(\mu,\nu) be a coupling, with quadratic cost I(π)I(\pi), a nonnegative real number by Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (iii). Let pr1,pr2:Rd+d→Rd\mathrm{pr}_{1},\mathrm{pr}_{2}:\mathbb{R}^{d+d}\to\mathbb{R}^{d} be the coordinate projections, and for z∈Rd+dz\in\mathbb{R}^{d+d} write x=pr1(z)x=\mathrm{pr}_{1}(z) and y=pr2(z)y=\mathrm{pr}_{2}(z). The spaces L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) and L2(π;Rd)L^{2}(\pi;\mathbb{R}^{d}) of square-integrable vector fields, the latter read with d+dd+d in place of qq and dd in place of rr, are those fixed there, with inner products ⟨⋅,⋅⟩μ\langle\cdot,\cdot\rangle_{\mu}, ⟨⋅,⋅⟩π\langle\cdot,\cdot\rangle_{\pi} and norms ∥⋅∥μ\lVert\cdot\rVert_{\mu}, ∥⋅∥π\lVert\cdot\rVert_{\pi}; id\mathrm{id} is the identity map of Rd\mathbb{R}^{d}, which is Borel, being continuous; push-forwards are those of Probability Measures on Euclidean Space and Random Vectors: Standing Notation (iv); and m(μ)∈Rdm(\mu)\in\mathbb{R}^{d} is the mean of μ\mu. Then the following hold.

1. (The displacement pairing) Let η∈L2(μ;Rd)\eta\in L^{2}(\mu;\mathbb{R}^{d}). For every representative of η\eta the function Rd+d→R\mathbb{R}^{d+d}\to\mathbb{R} with value η(x)⋅(y−x)\eta(x)\cdot(y-x) at zz is Borel and integrable with respect to π\pi, and its integral does not depend on the representative chosen. That integral,

J(η,π)=∫Rd+dη(x)⋅(y−x) π(dz)∈R,\mathcal{J}(\eta,\pi)=\int_{\mathbb{R}^{d+d}}\eta(x)\cdot(y-x)\,\pi(dz)\in\mathbb{R},

is called the displacement pairing of η\eta along π\pi.

2. (Bound) For every η∈L2(μ;Rd)\eta\in L^{2}(\mu;\mathbb{R}^{d}),

∣J(η,π)∣≤∥η∥μ I(π).\bigl|\mathcal{J}(\eta,\pi)\bigr|\le\lVert\eta\rVert_{\mu}\,\sqrt{I(\pi)} .

3. (Linearity in the field) For all η,ξ∈L2(μ;Rd)\eta,\xi\in L^{2}(\mu;\mathbb{R}^{d}) and all a,b∈Ra,b\in\mathbb{R},

J(a η+b ξ,π)=a J(η,π)+b J(ξ,π).\mathcal{J}(a\,\eta+b\,\xi,\pi)=a\,\mathcal{J}(\eta,\pi)+b\,\mathcal{J}(\xi,\pi).

4. (Displacement couplings) Let S:Rd→RdS:\mathbb{R}^{d}\to\mathbb{R}^{d} be Borel and satisfy ∫Rd∥S−id∥2 dμ<∞\int_{\mathbb{R}^{d}}\lVert S-\mathrm{id}\rVert^{2}\,d\mu<\infty, where S−idS-\mathrm{id} denotes the map x↦S(x)−xx\mapsto S(x)-x; it is Borel because each of its components is a difference of Borel real functions, hence Borel by claim 2 of Arithmetic of Measurable Real- and [0,∞]-Valued Maps, and a map into Rd\mathbb{R}^{d} with Borel components is Borel by Probability Measures on Euclidean Space and Random Vectors: Standing Notation (ii). Then the class of S−idS-\mathrm{id} belongs to L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) and is again written S−idS-\mathrm{id}, the push-forward S#μS_{\#}\mu belongs to P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}), the coupling πS=(id,S)#μ\pi_{S}=(\mathrm{id},S)_{\#}\mu belongs to Π(μ,S#μ)\Pi(\mu,S_{\#}\mu) with

I(πS)=∥S−id∥μ2,I(\pi_{S})=\lVert S-\mathrm{id}\rVert_{\mu}^{2},

and for every η∈L2(μ;Rd)\eta\in L^{2}(\mu;\mathbb{R}^{d}),

J(η,πS)=⟨η, S−id⟩μ.\mathcal{J}(\eta,\pi_{S})=\langle\eta,\,S-\mathrm{id}\rangle_{\mu}.

5. (Constant fields) Let c∈Rdc\in\mathbb{R}^{d} and let η\eta be the class in L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) of the constant map with value cc, which is Borel, being continuous, and square-integrable against μ\mu. Then

J(η,π)=c⋅(m(ν)−m(μ)).\mathcal{J}(\eta,\pi)=c\cdot\bigl(m(\nu)-m(\mu)\bigr).

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