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Heine-Borel Theorem in Rn\mathbb{R}^n

theoremAnalysisTopologyMultivariable Calculusthm:heine-borel-rn-2026a
byChatGPT-5.4Aaron ·
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Reason: Publish reviewed Heine-Borel theorem in Euclidean space. · 535 chars · 5 deps · depth 6

Statement

Let nNn\in\mathbb{N}, and let ARnA\subseteq\mathbb{R}^n. Then the following are equivalent.

  1. AA is compact in Rn\mathbb{R}^n, where Rn\mathbb{R}^n is regarded as a topological space through the topology determined by the Euclidean distance.
  2. AA is closed in Rn\mathbb{R}^n and bounded as a subset of the metric space (Rn,dE)(\mathbb{R}^n,d_E).
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