TheoremBase

Integrals over Measurable Subsets

The integral over a measurable set A is the integral of the map multiplied by the indicator of A; it reduces to the ordinary integral when A is the whole space, exists for integrable maps, is additive over disjoint sets, increases with A for nonnegative maps, and vanishes on sets of measure zero.

Statement

In the setting of Measurable Functions and the Lebesgue Integral: Notation, let (X,F,μ)(X,\mathcal{F},\mu) be a measure space.

Integrals over a subset as integrals over XX: nonnegative functions. Let f∈M+f\in\mathcal{M}^{+} and A∈FA\in\mathcal{F}. Then f1A∈M+f\mathbf{1}_{A}\in\mathcal{M}^{+} and, for the integral over AA of f∈M+f\in\mathcal{M}^{+},

∫Af dμ=∫Xf1A dμ.\int_{A}f\,d\mu=\int_{X}f\mathbf{1}_{A}\,d\mu .

Integrals over a subset as integrals over XX: integrable functions. Let f:X→Rf:X\to\mathbb{R} be measurable, let A∈FA\in\mathcal{F}, and let f1Af\mathbf{1}_{A} be the product of the real-valued functions ff and 1A\mathbf{1}_{A}. Then ff is integrable on AA if and only if f1A∈L1(μ)f\mathbf{1}_{A}\in\mathcal{L}^{1}(\mu), and in that case, for the integral over AA of an integrable function and the integral of f1A∈L1(μ)f\mathbf{1}_{A}\in\mathcal{L}^{1}(\mu),

∫Af dμ=∫Xf1A dμ.\int_{A}f\,d\mu=\int_{X}f\mathbf{1}_{A}\,d\mu .

Nonnegative real-valued functions. Let f:X→Rf:X\to\mathbb{R} be measurable with f(x)≥0f(x)\ge0 for every x∈Xx\in X, and let A∈FA\in\mathcal{F}. Then f∈M+f\in\mathcal{M}^{+} (Measurable Maps: Generators, Composition, Continuous Maps, Restrictions, and Criteria for Real- and [0,∞]-Valued Maps (vii)), and ff is integrable on AA if and only if ∫Af dμ<∞\int_{A}f\,d\mu<\infty for the integral over AA of f∈M+f\in\mathcal{M}^{+}; in that case this integral is a real number, and it equals the integral of ff over AA as an integrable function.

Zero extensions. Let A∈FA\in\mathcal{F}, and let g:A→Rg:A\to\mathbb{R} and g~:X→R\tilde g:X\to\mathbb{R} be functions with

g~(x)=g(x)(x∈A),g~(x)=0(x∈X∖A).\tilde g(x)=g(x)\quad(x\in A),\qquad\tilde g(x)=0\quad(x\in X\setminus A).

Then gg is measurable for FA\mathcal{F}_{A} if and only if g~\tilde g is measurable for F\mathcal{F}; in that case g∈L1(A,FA,μA)g\in\mathcal{L}^{1}(A,\mathcal{F}_{A},\mu_{A}) if and only if g~∈L1(μ)\tilde g\in\mathcal{L}^{1}(\mu), and then, for the integrals of these elements of L1(A,FA,μA)\mathcal{L}^{1}(A,\mathcal{F}_{A},\mu_{A}) and L1(μ)\mathcal{L}^{1}(\mu),

∫g dμA=∫Xg~ dμ.\int g\,d\mu_{A}=\int_{X}\tilde g\,d\mu .

Likewise, let g:A→[0,∞]g:A\to[0,\infty] and g~:X→[0,∞]\tilde g:X\to[0,\infty] be functions with the same two properties. Then gg is measurable for FA\mathcal{F}_{A} if and only if g~\tilde g is measurable for F\mathcal{F}, and in that case ∫g dμA=∫Xg~ dμ\int g\,d\mu_{A}=\int_{X}\tilde g\,d\mu, for the integrals of g∈M+(A,FA)g\in\mathcal{M}^{+}(A,\mathcal{F}_{A}) and g~∈M+\tilde g\in\mathcal{M}^{+}.

The whole space. For f∈M+f\in\mathcal{M}^{+}, the integral of ff over XX of Integrals of Functions over a Measurable Subset (ii) is the integral ∫Xf dμ\int_{X}f\,d\mu of f∈M+f\in\mathcal{M}^{+}. A measurable function f:X→Rf:X\to\mathbb{R} is integrable on XX if and only if f∈L1(μ)f\in\mathcal{L}^{1}(\mu), and in that case the integral of ff over XX of Integrals of Functions over a Measurable Subset (iv) is the integral ∫Xf dμ\int_{X}f\,d\mu of f∈L1(μ)f\in\mathcal{L}^{1}(\mu).

Integrable functions are integrable on every measurable subset. Every f∈L1(μ)f\in\mathcal{L}^{1}(\mu) is integrable on every A∈FA\in\mathcal{F}.

Additivity over disjoint sets. Let A,B∈FA,B\in\mathcal{F} with A∩B=∅A\cap B=\emptyset. Then A∪B∈FA\cup B\in\mathcal{F}, and for every f∈M+f\in\mathcal{M}^{+}, with the integrals over subsets of f∈M+f\in\mathcal{M}^{+} and the sum of [0,∞][0,\infty], and for every f∈L1(μ)f\in\mathcal{L}^{1}(\mu), which is integrable on AA, on BB and on A∪BA\cup B by (vi), with the integrals over subsets of an integrable function and the sum of R\mathbb{R},

∫A∪Bf dμ=∫Af dμ+∫Bf dμ.\int_{A\cup B}f\,d\mu=\int_{A}f\,d\mu+\int_{B}f\,d\mu .

Monotonicity in the set. Let f∈M+f\in\mathcal{M}^{+} and A,B∈FA,B\in\mathcal{F} with A⊆BA\subseteq B. Then, for the integrals over AA and BB of f∈M+f\in\mathcal{M}^{+},

∫Af dμ≤∫Bf dμ.\int_{A}f\,d\mu\le\int_{B}f\,d\mu .

Sets of measure zero. Let A∈FA\in\mathcal{F} with μ(A)=0\mu(A)=0. Then ∫Af dμ=0\int_{A}f\,d\mu=0 for every f∈M+f\in\mathcal{M}^{+}, with its integral over AA as an element of M+\mathcal{M}^{+}; and every measurable function f:X→Rf:X\to\mathbb{R} is integrable on AA, with ∫Af dμ=0\int_{A}f\,d\mu=0 for its integral over AA as an integrable function.

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