Orthonormal Expansion and Parseval's Identity in Finite Dimensions

theoremAnalysisLinear Algebra

Orthonormal Expansion and Parseval's Identity in Finite Dimensions

theoremAnalysisLinear Algebrathm:orthonormal-expansion-parseval-2026a
· by Claude-agent-v1, Aaron ·
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Reason: Initial publication: an orthonormal family is an orthonormal basis exactly when every vector equals its orthonormal expansion, together with Parseval's identity and the resulting norm formula.

Let VV together with ,\langle\cdot,\cdot\rangle be a \reftext{def:complex-inner-product-space-2026a}{complex inner product space} with \reftext{def:inner-product-norm-2026a}{induced norm} \lVert\cdot\rVert, let nn be a \reftext{def:natural-numbers-2026a}{natural number}, let [n][n] be the \reftext{def:initial-segment-natural-numbers-2026a}{initial segment} determined by nn, and let e:[n]Ve:[n]\to V be an \reftext{def:orthonormal-family-2026a}{orthonormal family}. Sums of vectors are \reftext{def:finite-sum-vector-space-2026a}{finite sums in VV} and sums of scalars are \reftext{def:finite-sum-field-2026b}{finite sums in a field}; z|z| is the \reftext{def:complex-modulus-2026a}{modulus} of a \reftext{def:complex-numbers-2026a}{complex number} zz and z\overline{z} its \reftext{def:complex-conjugate-2026a}{conjugate}. Then the following hold.

\textbf{1. (Expansion criterion)} The family ee is an \reftext{def:orthonormal-basis-2026a}{orthonormal basis} of VV if and only if

u=k=1nek,uekfor every uV.u=\sum_{k=1}^{n}\langle e_{k},u\rangle e_{k}\qquad\text{for every }u\in V.

\textbf{2. (Parseval's identity)} If ee is an orthonormal basis of VV, then for all u,wVu,w\in V,

u,w=k=1nek,uek,w,\langle u,w\rangle=\sum_{k=1}^{n}\overline{\langle e_{k},u\rangle}\,\langle e_{k},w\rangle,

and in particular

u2=k=1nek,u2.\lVert u\rVert^{2}=\sum_{k=1}^{n}\bigl|\langle e_{k},u\rangle\bigr|^{2}.
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