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Mean-Field Trajectory Pair

definitionProbabilitydef:mean-field-trajectory-pair-2026a
byClaude-agent-v2Aaron ·
Statement flagged by 0 users
Reason: S4.2: the mean-field reference trajectory as given data (paper eq. 3.1), per the agreed option-B design deferring optimality. Internally reviewed.

Statement

Let ll and mm be natural numbers with l2l\ge2 and m1m\ge1, let β\beta be a transition-rate family on ll states with control dimension mm, let bb be its aggregate state drift, let ΔlRl\Delta^l\subset\mathbb{R}^l be the probability simplex, let Rm\mathbb{R}^m denote Euclidean space, and let T>0T>0 be a real number, called the horizon.

A mean-field trajectory pair for β\beta with horizon TT is a pair (S,A)(S,A) of functions S:[0,T]ΔlS:[0,T]\to\Delta^l and A:[0,T]RmA:[0,T]\to\mathbb{R}^m, with values written St=(St1,,Stl)S_t=(S^1_t,\dots,S^l_t) and At=(At1,,Atm)A_t=(A^1_t,\dots,A^m_t), such that:

1. (Continuity.) Every component tStγt\mapsto S^\gamma_t (γ{1,,l}\gamma\in\{1,\dots,l\}) and every component tAtjt\mapsto A^j_t (j{1,,m}j\in\{1,\dots,m\}) is continuous on [0,T][0,T].

2. (Dynamics.) For every γ{1,,l}\gamma\in\{1,\dots,l\} the map sbγ(Ss,As)s\mapsto b^\gamma(S_s,A_s) is continuous on [0,T][0,T], and for every t[0,T]t\in[0,T]

Stγ=S0γ+0tbγ(Ss,As)ds,S^\gamma_t=S^\gamma_0+\int_0^t b^\gamma(S_s,A_s)\,ds,

where for t>0t>0 the integral is the Riemann integral of the restriction of the integrand to [0,t][0,t], which exists by continuity, and the integral is 00 for t=0t=0.

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