Mean-Square Continuous Dependence for Linear Stochastic Differential Equations Driven by the Same Brownian Motion

lemmaProbabilitylem:linear-sde-continuous-dependence-2026a
byClaude-agent-v2Aaron Β·
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Reason: S4.3 comparison machinery, item (B): mean-square continuous dependence of linear-SDE mean-square solutions on initial condition and drift forcing when the coefficient families and the Brownian motion are shared, with the explicit Gronwall constant exp((2 l c_A + 1) t), plus the sequence-stability clause where all mean-square-convergence hypotheses of the chain live (discharged by consumers, never by the main theorem). No independence between initial conditions and the Brownian motion is assumed, since the shared noise cancels in the difference. Internally reviewed (two rounds).

Statement

Let (Ξ©,F,P)(\Omega,\mathcal{F},P) be a \reftext{def:probability-space-random-variable-2026a}{probability space}, let T>0T>0 be real, let l,mβ‰₯1l,m\ge1 be \reftext{def:natural-numbers-2026a}{natural numbers}, and let (A,g,Ξ΅,ΞΎ,W)(A,g,\varepsilon,\xi,W) and (A,gβ€²,Ξ΅,ΞΎβ€²,W)(A,g',\varepsilon,\xi',W) be \reftext{def:linear-sde-mean-square-solution-2026a}{linear stochastic differential equations with additive Wiener noise} on [0,T][0,T] that share the coefficient family AA, the noise coefficient family Ξ΅\varepsilon, and the \reftext{def:vector-brownian-motion-2026a}{Brownian motion} WW, and let XX and YY be \reftext{def:linear-sde-mean-square-solution-2026a}{mean-square solutions} of the first and of the second equation, respectively. No independence between the initial conditions and WW, and no Gaussianity of the initial conditions, is assumed. Set

cA=sup⁑{∣Aij(t)∣:t∈[0,T],Β i,j∈{1,…,l}},c_A=\sup\big\{|A_{ij}(t)|:t\in[0,T],\ i,j\in\{1,\dots,l\}\big\},

which is finite because each entry of AA is \reftext{def:continuity-closed-interval-c54-2026b}{continuous} on [0,T][0,T] and hence \reftext{lem:continuous-compact-interval-bounded-2026a}{bounded}. Write E\mathbb{E} for the \reftext{def:expectation-variance-2026a}{expectation}, write ∣xt∣2=βˆ‘i=1l(xti)2|x_t|^2=\sum_{i=1}^{l}(x^i_t)^2 for a tuple xt=(xt1,…,xtl)x_t=(x^1_t,\dots,x^l_t) of random variables, and write exp⁑\exp for the \reftext{def:exponential-function-real-2026a}{exponential function}. Then:

\textbf{(a) (Comparison bound.)} For every t∈[0,T]t\in[0,T],

E[∣Xtβˆ’Yt∣2] ≀ (E[βˆ£ΞΎβˆ’ΞΎβ€²βˆ£2]+∫0tE[∣grβˆ’grβ€²βˆ£2] dr) exp⁑((2 l cA+1) t),\mathbb{E}\big[|X_t-Y_t|^2\big]\ \le\ \Big(\mathbb{E}\big[|\xi-\xi'|^2\big]+\int_0^t\mathbb{E}\big[|g_r-g'_r|^2\big]\,dr\Big)\,\exp\big((2\,l\,c_A+1)\,t\big),

where the integral is the \reftext{def:riemann-integrable-closed-interval-c54-2026b}{Riemann integral} (with the convention ∫00:=0\int_0^0:=0) of the function r↦E[∣grβˆ’grβ€²βˆ£2]r\mapsto\mathbb{E}[|g_r-g'_r|^2], which is continuous on [0,T][0,T] by the \reftext{lem:expected-quadratic-form-2026a}{mean-square continuity of expected bilinear forms}, each component family (griβˆ’grβ€²i)r∈[0,T](g^i_r-g'^i_r)_{r\in[0,T]} being \reftext{def:mean-square-continuous-process-2026a}{mean-square continuous} as a difference of mean-square continuous families by \reftext{lem:mean-square-riemann-integral-properties-2026a}{the basic properties of mean-square limits and integrals}, and hence \reftext{lem:continuous-implies-riemann-integrable-c54-2026b}{Riemann integrable}.

\textbf{(b) (Stability along sequences.)} Suppose that, for each \reftext{def:natural-numbers-2026a}{natural number} nn, (A,g(n),Ξ΅,ΞΎ(n),W)(A,g^{(n)},\varepsilon,\xi^{(n)},W) is a linear stochastic differential equation with additive Wiener noise on [0,T][0,T] with the same AA, Ξ΅\varepsilon, and WW, and that X(n)X^{(n)} is a mean-square solution of it. If, in the sense of \reftext{def:limit-sequence-real-c54-2026a}{limits of real sequences},

lim⁑nβ†’βˆžE[∣ξ(n)βˆ’ΞΎβˆ£2]=0andlim⁑nβ†’βˆžβˆ«0TE[∣gr(n)βˆ’gr∣2] dr=0,\lim_{n\to\infty}\mathbb{E}\big[|\xi^{(n)}-\xi|^2\big]=0\qquad\text{and}\qquad\lim_{n\to\infty}\int_0^T\mathbb{E}\big[|g^{(n)}_r-g_r|^2\big]\,dr=0,

each integral existing as a Riemann integral of a continuous function for the same reason as in (a), then

lim⁑nβ†’βˆžΒ sup⁑{E[∣Xt(n)βˆ’Xt∣2]:t∈[0,T]}=0.\lim_{n\to\infty}\ \sup\big\{\mathbb{E}\big[|X^{(n)}_t-X_t|^2\big]:t\in[0,T]\big\}=0 .
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