Along a coupling of finite noise cost the displacement is a square-integrable noise field whose squared norm is the noise cost; pairing it with a noise field gives a bounded linear functional, computed explicitly along displacement couplings. Also: the cross pairing of two noise fields along any coupling, the polarisation identity for their discrepancy, and a noise field whose pairings vanish to first order is zero.
1. (The displacement field) Let ν∈P(X) and π∈Πa(μ,ν). The map δ:X×X→Xa with δ(z)=y−x for z∈Da and δ(z)=0X for z∈(X×X)∖Da is measurable into Xa and square-integrable with respect to π, and its class in L2(π;Xa), again written δ, satisfies
∥δ∥π2=Ia(π).
2. (The noise displacement pairing) Let ν∈P(X), π∈Πa(μ,ν) and η∈L2(μ;Xa), and let δ be the displacement field of claim 1 for π. For every representative of η the function X×X→R with value ⟨η(x),δ(z)⟩a at z is Borel and integrable with respect to π, and its integral does not depend on the representative chosen. That integral,
Ja(η,π)=∫X×X⟨η(x),δ(z)⟩aπ(dz)∈R,
whose integrand equals ⟨η(x),y−x⟩a at every z∈Da, is called the noise displacement pairing of η along π.
3. (Bound) For ν∈P(X), π∈Πa(μ,ν) and η∈L2(μ;Xa),
Ja(η,π)≤∥η∥μIa(π).
4. (Linearity in the field) For ν∈P(X), π∈Πa(μ,ν), η,ξ∈L2(μ;Xa) and s,t∈R,
Ja(sη+tξ,π)=sJa(η,π)+tJa(ξ,π).
5. (Displacement couplings) Let h∈L2(μ;Xa), let h:X→Xa also denote any representative of it, and let t∈R; the following conclusions hold for every such representative. Then the map St:X→X, St(x)=x+th(x), is Borel, the coupling πt=(id,St)#μ belongs to Πa(μ,(St)#μ), and
Ia(πt)=t2∥h∥μ2,Ja(η,πt)=t⟨η,h⟩μfor every η∈L2(μ;Xa).
If moreover μ∈Pρa, then (St)#μ∈Pρa.
6. (The cross pairing) Let ν∈P(X), π∈Π(ν,μ), q∈L2(ν;Xa) and η∈L2(μ;Xa). For all representatives of q and of η the function X×X→R with value ⟨q(x),η(y)⟩a at z is Borel and integrable with respect to π, and its integral does not depend on the representatives chosen. That integral,
Ka(q,η,π)=∫X×X⟨q(x),η(y)⟩aπ(dz)∈R,
is called the cross pairing of q and η along π. It satisfies ∣Ka(q,η,π)∣≤∥q∥ν∥η∥μ. Moreover, for all representatives the function X×X→R with value ∣q(x)−η(y)∣a2 at z is Borel, nonnegative and integrable with respect to π, its integral, called the discrepancy of q and η along π, does not depend on the representatives chosen, and
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