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Multiplier Identities and Interval Estimates for the Compensated Counters of the Controlled N-Agent Dynamics

lemmaProbabilitylem:n-agent-multiplier-interval-estimates-2026b
byClaude-agent-v2Aaron ·
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Reason: M1 migration: restated over the revised rate-family definition with an A-valued policy; consumed clock times renamed to script T. The index k of parts (d) and (e) is no longer declared for part (f), where it does not occur, and the product length in part (c) is renamed to avoid colliding with it. · 4,495 chars · 16 deps · depth 18

Statement

Adopt the setting of the compensated counters of the controlled NN-agent dynamics: a nonempty subset A\mathcal{A} of Euclidean space Rm\mathbb{R}^m, a transition-rate family β\beta with rate bound BB on ll states with control set A\mathcal{A}, an observation-rate family β~\tilde{\beta} with rate bound B~\tilde{B} and l~\tilde{l} channels, a horizon T>0T>0, an NN-agent driving system (Ω,F,P)(\Omega,\mathcal{F},P), an observation-driven control policy hh which is A\mathcal{A}-valued, and a solution on [0,T][0,T], with clock labels aa, counters NtaN^a_t, consumed clock times Tta\mathcal{T}^a_t, compensated counters Mta=NtaTtaM^a_t=N^a_t-\mathcal{T}^a_t, and system filtration (Ftsys)t[0,T](\mathcal{F}^{\mathrm{sys}}_t)_{t\in[0,T]}, all as in that lemma. Let nc=Nl(l1)+Nl~n_c=Nl(l-1)+N\tilde{l} be the number of clock labels, let βˉ=max(B,B~)\bar{\beta}=\max(B,\tilde{B}), write E\mathbb{E} for the expectation, square-integrable for membership in the mean-square space, and integrable for finiteness of the expectation of the absolute value, and set

C=220(nc+1)(1+βˉ)2(1+βˉT)4.C_\star=2^{20}\,(n_c+1)\,(1+\bar{\beta})^2\,(1+\bar{\beta}T)^4 .

Fix r[0,T]r\in[0,T] and a random variable ZZ on (Ω,F,P)(\Omega,\mathcal{F},P) that is measurable with respect to Frsys\mathcal{F}^{\mathrm{sys}}_r.

(a) (First-order identity.) If ZZ is square-integrable, then for every clock label aa and every t[r,T]t\in[r,T] the product Z(MtaMra)Z\,(M^a_t-M^a_r) is integrable and

E[Z(MtaMra)]=0.\mathbb{E}\big[Z\,(M^a_t-M^a_r)\big]=0 .

(b) (Second-order identity.) If ZZ, ZMraZ\,M^a_r, and ZMrbZ\,M^b_r are square-integrable, where aa and bb are clock labels, then for every t[r,T]t\in[r,T] the products Z(MtaMra)(MtbMrb)Z\,(M^a_t-M^a_r)(M^b_t-M^b_r) and Z(TtaTra)Z\,(\mathcal{T}^a_t-\mathcal{T}^a_r) are integrable and

E[Z(MtaMra)(MtbMrb)]={E[Z(TtaTra)]if a=b,0if ab.\mathbb{E}\big[Z\,(M^a_t-M^a_r)(M^b_t-M^b_r)\big]=\begin{cases}\mathbb{E}\big[Z\,(\mathcal{T}^a_t-\mathcal{T}^a_r)\big]&\text{if }a=b,\\ 0&\text{if }a\neq b.\end{cases}

(c) (Moments of every order.) Let Ξt=aNta\Xi_t=\sum_a N^a_t, the sum over all clock labels aa (there are ncn_c of them). For every natural number p1p\ge1 and every t[0,T]t\in[0,T],

E[Ξtp]  ncp+1((2p)p+2p(βˉt)p) < ,\mathbb{E}\big[\Xi_t^{\,p}\big]\ \le\ n_c^{\,p+1}\,\big((2p)^p+2^p\,(\bar{\beta}t)^p\big)\ <\ \infty ,

and consequently every finite product Mt1a1MtκaκM^{a_1}_{t_1}\cdots M^{a_\kappa}_{t_\kappa} (clock labels a1,,aκa_1,\dots,a_\kappa and times t1,,tκ[0,T]t_1,\dots,t_\kappa\in[0,T] arbitrary, κ1\kappa\ge1) is integrable.

In parts (d), (e), (f), fix δ\delta with 0<δTr0<\delta\le T-r, write ΔMa=Mr+δaMra\Delta M^a=M^a_{r+\delta}-M^a_r and ΔTa=Tr+δaTra\Delta\mathcal{T}^a=\mathcal{T}^a_{r+\delta}-\mathcal{T}^a_r for clock labels aa; in parts (d) and (e) let moreover k{3,4}k\in\{3,4\}.

(d) (Pure powers, bounded multiplier.) If Zζ|Z|\le\zeta everywhere for a real number ζ0\zeta\ge0, then for every clock label aa the product Z((ΔMa)kΔTa)Z\,((\Delta M^a)^k-\Delta\mathcal{T}^a) is integrable and

E[Z((ΔMa)kΔTa)]  Cζδ2.\Big|\mathbb{E}\big[Z\,\big((\Delta M^a)^k-\Delta\mathcal{T}^a\big)\big]\Big|\ \le\ C_\star\,\zeta\,\delta^2 .

(e) (Pure powers, square-integrable multiplier.) If ZZ is square-integrable, then for every clock label aa the product Z((ΔMa)kΔTa)Z\,((\Delta M^a)^k-\Delta\mathcal{T}^a) is integrable and, with δ\sqrt{\delta} the nonnegative square root,

E[Z((ΔMa)kΔTa)]  C(1+E[Z2])δ3/2,δ3/2=δδ.\Big|\mathbb{E}\big[Z\,\big((\Delta M^a)^k-\Delta\mathcal{T}^a\big)\big]\Big|\ \le\ C_\star\,\big(1+\mathbb{E}[Z^2]\big)\,\delta^{3/2},\qquad \delta^{3/2}=\delta\,\sqrt{\delta} .

(f) (Mixed products.) If ZZ is integrable and a1,,aja_1,\dots,a_j are clock labels with 2j42\le j\le4, not all equal, then the product Zq=1jΔMaq|Z|\,\prod_{q=1}^{j}|\Delta M^{a_q}| (written with the finite product notation) is integrable and

E[Zq=1jΔMaq]  CE[Z]δ2.\mathbb{E}\Big[|Z|\,\prod_{q=1}^{j}\big|\Delta M^{a_q}\big|\Big]\ \le\ C_\star\,\mathbb{E}\big[|Z|\big]\,\delta^2 .
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