Reason: New lemma completing the S4.3 infrastructure: multiplier forms of the fresh-start interval estimates (exact first/second-order identities for L^2 multipliers, third/fourth-order compensated estimates for bounded and square-integrable multipliers, mixed-label product bounds, and moments of every order via Poisson domination). Internally reviewed; strict validation clean; the sole rendering advisory is the known tokenizer artifact shared with sibling items.
\textbf{(a) (First-order identity.)} If Z is square-integrable, then for every clock label a and every tβ[r,T] the product Z(MtaββMraβ) is integrable and
E[Z(MtaββMraβ)]=0.
\textbf{(b) (Second-order identity.)} If Z, ZMraβ, and ZMrbβ are square-integrable, where a and b are clock labels, then for every tβ[r,T] the products Z(MtaββMraβ)(MtbββMrbβ) and Z(AtaββAraβ) are integrable and
\textbf{(c) (Moments of every order.)} Let Ξtβ=βaβNtaβ, the sum over all clock labels a (there are ncβ of them). For every \reftext{def:natural-numbers-2026a}{natural number} pβ₯1 and every tβ[0,T],
and consequently every finite product Mt1βa1βββ―Mtkβakββ (clock labels a1β,β¦,akβ and times t1β,β¦,tkββ[0,T] arbitrary, kβ₯1) is integrable.
In parts (d), (e), (f), fix Ξ΄ with 0<Ξ΄β€Tβr, write ΞMa=Mr+Ξ΄aββMraβ and ΞAa=Ar+Ξ΄aββAraβ for clock labels a, and let kβ{3,4}.
\textbf{(d) (Pure powers, bounded multiplier.)} If β£Zβ£β€ΞΆ everywhere for a real number ΞΆβ₯0, then for every clock label a the product Z((ΞMa)kβΞAa) is integrable and
βE[Z((ΞMa)kβΞAa)]βΒ β€Β CββΞΆΞ΄2.
\textbf{(e) (Pure powers, square-integrable multiplier.)} If Z is square-integrable, then for every clock label a the product Z((ΞMa)kβΞAa) is integrable and, with Ξ΄β the \reftext{thm:nonnegative-real-has-unique-square-root-2026a}{nonnegative square root},
\textbf{(f) (Mixed products.)} If Z is integrable and a1β,β¦,ajβ are clock labels with 2β€jβ€4, \textbf{not all equal}, then the product β£Zβ£βq=1jββ£ΞMaqββ£ (written with the \reftext{def:finite-product-notation-2026a}{finite product notation}) is integrable and
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