The Integral over the Unit Cell of a Product of One-Variable Functions
lemmaAnalysisMultivariable Calculuslem:product-function-integral-cell-2026aFor bounded Borel functions of one variable, the integral over the torus of the product of their coordinate evaluations is the product of their integrals over the unit interval.
We work in the setting of The Flat Torus: Standing Notation, used here with a natural number satisfying ; the initial segments , Euclidean space , the half-open unit cell , the measure space together with the notation , and the integral and the notion of an integrable map are the ones fixed there. Let be the Borel -algebra of the real line and let be Lebesgue measure on it. Finite products of real numbers are the finite products of that definition, formed in the field of real numbers.
Put
Then is an interval, since and whenever with ; hence by Borel Sigma-Algebra on the Real Line. The closed intervals and are intervals too, hence also lie in , and claim 4 of Existence of Lebesgue Measure on the Real Line gives and . Since , is finite and , claim 3 of Basic Properties of a Measure gives . Let denote the restriction of to furnished by claim 1 of that lemma, so that and . By the description of the cell recorded in The Half-Open Unit Cell Tiles Euclidean Space §cell, a point lies in if and only if for every .
Let be measurable with respect to , for every . Then the following hold.
1. (The product function)¶ Setting
defines a map , and is measurable with respect to .
2. (The integral of the product)¶ Suppose in addition that for every there is a real number with for every , where is the absolute value. Then each is integrable with respect to , the map is integrable with respect to , and
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