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Functions and Function-Valued Operators Given by Integrals over Subintervals

Under dependent choice, integrals over the subintervals [a,t] of [a,b] define functions of t, for scalar, vector-valued and parametric integrands, and the assignments g ↦ (t ↦ ∫ over [a,t] of g) and z ↦ (r ↦ F(r,z(r))) are functions between the relevant sets of functions.

Statement

In the setting of Integrals over Subintervals of a Closed Interval: Notation, assume the axiom of dependent choice. For sets YY and ZZ, YZY^{Z} is the set of functions from ZZ to YY. For a function h:[a,b]×[a,b]→Rnh:[a,b]\times[a,b]\to\mathbb{R}^{n} and t∈[a,b]t\in[a,b], h(t,⋅):[a,b]→Rnh(t,\cdot):[a,b]\to\mathbb{R}^{n} is the function s↦h(t,s)s\mapsto h(t,s) of Maps Formed Pointwise: Constant Maps, Pairs of Values, Maps Applied to Values, and Families of Maps (iv).

Scalar integrands. For every f∈L1([a,b])f\in\mathcal{L}^{1}([a,b]) there is exactly one function X:[a,b]→RX:[a,b]\to\mathbb{R} with

X(t)=∫[a,t]f dλ(t∈[a,b]).X(t)=\int_{[a,t]}f\,d\lambda\qquad(t\in[a,b]).

Vector-valued integrands. For every g∈L1([a,b];Rn)g\in\mathcal{L}^{1}([a,b];\mathbb{R}^{n}) there is exactly one function X:[a,b]→RnX:[a,b]\to\mathbb{R}^{n} with

X(t)=∫[a,t]g dλ(t∈[a,b]).X(t)=\int_{[a,t]}g\,d\lambda\qquad(t\in[a,b]).

The integral operator. There is exactly one function J:L1([a,b];Rn)→(Rn)[a,b]\mathcal{J}:\mathcal{L}^{1}([a,b];\mathbb{R}^{n})\to(\mathbb{R}^{n})^{[a,b]} with

J(g)(t)=∫[a,t]g dλ(g∈L1([a,b];Rn), t∈[a,b]).\mathcal{J}(g)(t)=\int_{[a,t]}g\,d\lambda\qquad(g\in\mathcal{L}^{1}([a,b];\mathbb{R}^{n}),\ t\in[a,b]).

The substitution operator. For every function F:[a,b]×Rn→RnF:[a,b]\times\mathbb{R}^{n}\to\mathbb{R}^{n} there is exactly one function Θ:(Rn)[a,b]→(Rn)[a,b]\Theta:(\mathbb{R}^{n})^{[a,b]}\to(\mathbb{R}^{n})^{[a,b]} with

Θ(z)(r)=F(r,z(r))(z∈(Rn)[a,b], r∈[a,b]).\Theta(z)(r)=F(r,z(r))\qquad(z\in(\mathbb{R}^{n})^{[a,b]},\ r\in[a,b]).

Integrands depending on the endpoint. Let h:[a,b]×[a,b]→Rnh:[a,b]\times[a,b]\to\mathbb{R}^{n} be a function with h(t,⋅)∈L1([a,b];Rn)h(t,\cdot)\in\mathcal{L}^{1}([a,b];\mathbb{R}^{n}) for every t∈[a,b]t\in[a,b]. There is exactly one function Y:[a,b]→RnY:[a,b]\to\mathbb{R}^{n} with

Y(t)=∫[a,t]h(t,s) ds(t∈[a,b]).Y(t)=\int_{[a,t]}h(t,s)\,ds\qquad(t\in[a,b]).

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