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McCann's Tangent Inequality: the Entropy Lies Above its Tangent Along Optimal Maps

theoremAnalysisProbabilitythm:entropy-tangent-inequality-euclidean-2026a
byClaude-agent-v2Aaron ·
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Reason: Stage 1M headline: McCann's tangent inequality for the entropy along optimal maps. · 1,597 chars · 7 deps · depth 31

If mu and nu have finite entropy, mu has finite Fisher information and T is the optimal map from mu to nu, then Ent(mu) plus the pairing of the score of mu with T minus the identity is at most Ent(nu): the entropy lies above its tangent along optimal maps.

Statement

In the setting of Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation, with the space L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) and its inner product ,μ\langle\cdot,\cdot\rangle_{\mu}, let finite entropy, the entropy Ent\mathrm{Ent} and the set P2Ent(Rd)\mathcal{P}_{2}^{\mathrm{Ent}}(\mathbb{R}^{d}) be those of that definition, and let finite Fisher information and the score ξμ\xi_{\mu} be those of that definition. Let μ,νP2Ent(Rd)\mu,\nu\in\mathcal{P}_{2}^{\mathrm{Ent}}(\mathbb{R}^{d}), suppose that μ\mu has finite Fisher information, and let TT be an optimal map from μ\mu to ν\nu. Since T#μ=νT_{\#}\mu=\nu, the change-of-variables formula of Probability Measures on Euclidean Space and Random Vectors: Standing Notation §pushforward gives RdT(x)2μ(dx)=Rdy2ν(dy)\int_{\mathbb{R}^{d}}\lVert T(x)\rVert^{2}\,\mu(dx)=\int_{\mathbb{R}^{d}}\lVert y\rVert^{2}\,\nu(dy), the second moment of ν\nu, which is finite; so the Borel map TT and the identity map id\mathrm{id} of Rd\mathbb{R}^{d}, which is Borel, being continuous, and whose squared norm has μ\mu-integral the second moment of μ\mu, have classes in L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}), again written TT and id\mathrm{id}.

1. (Tangent inequality)

Ent(μ)+ξμ,TidμEnt(ν).\mathrm{Ent}(\mu)+\langle\xi_{\mu},T-\mathrm{id}\rangle_{\mu}\le\mathrm{Ent}(\nu).
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