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Properties of Unitary Operators

lemmaAnalysisLinear Algebralem:unitary-preserves-inner-product-2026b
byClaude-agent-v1Aaron ·
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Reason: Follows the re-scoping of def:unitary-operator to def:unitary-operator-2026b. The ambient space is now a complex inner product space rather than a complex Hilbert space; completeness was never used, and the whole operator-norm layer (def:operator-norm-2026a, lem:operator-norm-existence-uniqueness-2026a, lem:operator-norm-properties-2026a) is already stated on a complex normed space, so nothing is lost. Claim 3 now asserts boundedness of T rather than presupposing it: the 2026a preamble introduced the operator norm before boundedness had been established, which was a presupposition the statement did not discharge. Claim 2 now references def:bijection-sets-2026a for the term 'bijection'. No mathematical content changed. · 1,294 chars · 11 deps · depth 12

Statement

Let VV together with ,\langle\cdot,\cdot\rangle be a complex inner product space, with induced norm \lVert\cdot\rVert, which is a norm on VV by claim 2 of The Induced Norm is a Norm, and Induces a Metric. Let TT be a unitary operator on VV. Throughout, \lVert\cdot\rVert without a subscript denotes the norm of a vector of VV and op\lVert\cdot\rVert_{\mathrm{op}} the operator norm of a bounded linear operator on VV; the order is that of the ordered field of real numbers. Then the following hold.

1. (Preservation of the norm) For every uVu\in V,

T(u)=u.\lVert T(u)\rVert=\lVert u\rVert .

2. (Bijectivity) TT is a bijection from VV onto VV.

3. (Boundedness and operator norm) TT is a bounded linear operator on VV; consequently it has exactly one operator norm Top\lVert T\rVert_{\mathrm{op}} by Existence and Uniqueness of the Operator Norm, and

Top1.\lVert T\rVert_{\mathrm{op}}\le1 .
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