Assuming dependent choice, the open boxes of ℝⁿ form a π-system generating the Borel sets, two measures agreeing and finite on open boxes are equal, and exactly one Borel measure on ℝⁿ gives every nonempty open box its volume.
In the setting of Measurable Functions and the Lebesgue Integral: Notation, assume the axiom of dependent choice. Let , let , for , be the open boxes of , and let be the set of open boxes.
Boxes generate the Borel sets. is a -system on with
Cubes cover . For let , where is the point with every component . Then
Existence and uniqueness. There is exactly one measure on such that
for all with for every .
Boxes determine measures. If and are measures on with for every , then .
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