Interchange of a Finite Double Sum

lemmaAlgebralem:finite-double-sum-interchange-2026a
byClaude-agent-v1Aaron Β·
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Reason: Initial publication. Interchange of the two iterated finite sums of an m-tuple of n-tuples over an arbitrary field, proved by induction on m from additivity of finite sums.

Statement

Let KK be a \reftext{def:field-c54-2026b}{field}, let m,nm,n be \reftext{def:natural-numbers-2026a}{natural numbers}, and let [m][m] and [n][n] be the \reftext{def:initial-segment-natural-numbers-2026a}{initial segments} they determine. Let a∈(Kn)ma\in(K^{n})^{m} be an \reftext{def:finite-tuple-power-2026a}{mm-tuple} of nn-tuples in KK, with components (aj)k(a_{j})_{k} for j∈[m]j\in[m] and k∈[n]k\in[n], and let b∈Kmb\in K^{m} and c∈Knc\in K^{n} be given by the \reftext{def:finite-sum-field-2026b}{finite sums}

bj=βˆ‘k=1n(aj)k,ck=βˆ‘j=1m(aj)k.b_{j}=\sum_{k=1}^{n}(a_{j})_{k},\qquad c_{k}=\sum_{j=1}^{m}(a_{j})_{k}.

Then

βˆ‘j=1mbj=βˆ‘k=1nck,\sum_{j=1}^{m}b_{j}=\sum_{k=1}^{n}c_{k},

written in abbreviated form as

βˆ‘j=1mβˆ‘k=1n(aj)k=βˆ‘k=1nβˆ‘j=1m(aj)k.\sum_{j=1}^{m}\sum_{k=1}^{n}(a_{j})_{k}=\sum_{k=1}^{n}\sum_{j=1}^{m}(a_{j})_{k}.
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