TheoremBase

Iterated Powers, Factorials, and Convergence of the Series of Powers over Factorials

Factorials are positive and nondecreasing, the series of powers of a nonnegative real number divided by factorials converges, and it dominates the two series of even and odd order that define cosine and sine.

Statement

In the setting of The Real Numbers: Standing Notation and Background, let AA be a real number with 0≤A0\le A. For k∈Nk\in\mathbb{N} let k!k! denote the factorial of kk, which by the finite-product definition used there is a real number, and let cnc^{n} denote the nnth power of a real number cc. Convergence of a series of real numbers and its sum are as defined there. Then the following hold.

1. (Doubling, iterated powers, and absolute values) Let the multiplication of the natural numbers be that of clauses 3 and 4 of that definition, let SS be its successor map, and for k∈Nk\in\mathbb{N} abbreviate

2k=k⋅2,2k+1=S(k⋅2).2k=k\cdot 2,\qquad 2k+1=S(k\cdot 2).

Then 2k=k+k2k=k+k and k<2kk<2k. Moreover, for every real number cc and all m,n∈Nm,n\in\mathbb{N},

c m⋅n=(cm)n,∣cn∣=∣c∣n,c^{\,m\cdot n}=\bigl(c^{m}\bigr)^{n}, \qquad \bigl|c^{n}\bigr|=|c|^{n},

where ∣t∣|t| denotes the absolute value of t∈Rt\in\mathbb{R}. In particular (−c)2n=c2n(-c)^{2n}=c^{2n} and (−c)2n+1=−c2n+1(-c)^{2n+1}=-c^{2n+1}.

2. (Factorials are positive and nondecreasing) For every k∈Nk\in\mathbb{N} one has 1≤k!1\le k!; in particular k!k! is positive and has a multiplicative inverse in R\mathbb{R}. Moreover m!≤n!m!\le n! for all m,n∈Nm,n\in\mathbb{N} with m≤nm\le n.

3. (The exponential majorant) The terms of the series ∑k=1∞Akk!\sum_{k=1}^{\infty}\dfrac{A^{k}}{k!} are nonnegative, and that series converges.

4. (The trigonometric majorants) For every k∈Nk\in\mathbb{N},

0≤A2k(2k)!≤(A2)kk!,0≤A2k+1(2k+1)!≤A⋅(A2)kk!.0\le\frac{A^{2k}}{(2k)!}\le\frac{(A^{2})^{k}}{k!}, \qquad 0\le\frac{A^{2k+1}}{(2k+1)!}\le A\cdot\frac{(A^{2})^{k}}{k!} .

Consequently the series

∑k=1∞A2k(2k)!and∑k=1∞A2k+1(2k+1)!\sum_{k=1}^{\infty}\frac{A^{2k}}{(2k)!} \qquad\text{and}\qquad \sum_{k=1}^{\infty}\frac{A^{2k+1}}{(2k+1)!}

converge.

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