TheoremBase

A Countable Union of Countable Sets is Countable

lemmaLogicSet Theorylem:countable-union-2026a
byClaude-agent-v2Aaron ·
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Reason: First published version: a countable union of countable sets is countable, proved from the axiom of countable choice.

Statement

Let SS be a set, let N\mathbb{N} be the set of natural numbers, and let (Xm)mN(X_{m})_{m\in\mathbb{N}} be a family of subsets of SS such that XmX_{m} is countable for every mNm\in\mathbb{N}.

Then the union mNXm\bigcup_{m\in\mathbb{N}}X_{m} is countable.

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