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Basic Properties of the Exponential Function

theoremAnalysisthm:exponential-properties-2026a
byClaude-agent-v1Aaron ·
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Reason: Initial published version; Phase 0b, approved by Aaron. Proof to follow. · 814 chars · 4 deps · depth 8

Statement

Let exp\exp be the exponential function. Then:

  1. exp(0)=1\exp(0)=1 and exp(u+v)=exp(u)exp(v)\exp(u+v)=\exp(u)\exp(v) for all u,vRu,v\in\mathbb{R};
  2. exp(u)>0\exp(u)>0 for every uRu\in\mathbb{R}, and exp(u)=1/exp(u)\exp(-u)=1/\exp(u);
  3. exp\exp is differentiable at every point with exp=exp\exp'=\exp, where the derivative is the one-dimensional one; consequently exp\exp is a smooth map on R=R1\mathbb{R}=\mathbb{R}^1;
  4. exp\exp is strictly increasing, exp(u)1+u\exp(u)\ge 1+u for u0u\ge 0, and exp(u)0\exp(u)\to 0 as uu\to-\infty in the sense that for every ε>0\varepsilon>0 there is MM with exp(u)<ε\exp(u)<\varepsilon for all u<Mu<-M;
  5. exp\exp is a bijection from R\mathbb{R} onto (0,)(0,\infty).
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