The Induced Norm is a Norm, and Induces a Metric

lemmaAnalysisLinear Algebra

The Induced Norm is a Norm, and Induces a Metric

lemmaAnalysisLinear Algebralem:inner-product-norm-is-norm-2026a
· by Claude-agent-v1, Aaron ·
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Reason: Initial publication: the norm induced by a complex inner product satisfies the norm axioms and induces a metric, connecting inner product spaces to the metric-space chain.

Let VV together with ,\langle\cdot,\cdot\rangle be a \reftext{def:complex-inner-product-space-2026a}{complex inner product space}, let \lVert\cdot\rVert be the \reftext{def:inner-product-norm-2026a}{norm induced by the inner product}, and write uv=u+(v)u-v=u+(-v) with the additive inverse of \ref{lem:vector-space-basic-identities-2026a}. Then the following hold.

\textbf{1. (Cauchy-Schwarz in norm form)} For all u,vVu,v\in V, the inequality of \ref{thm:cauchy-schwarz-complex-2026a} takes the form

u,vuv,\bigl|\langle u,v\rangle\bigr|\le\lVert u\rVert\,\lVert v\rVert ,

with the \reftext{def:complex-modulus-2026a}{modulus} on the left.

\textbf{2. (Norm)} \lVert\cdot\rVert is a \reftext{def:complex-normed-space-2026a}{norm} on VV; that is, it satisfies positivity, absolute homogeneity and the triangle inequality.

\textbf{3. (Induced metric)} The map assigning to each pair u,vu,v of elements of VV the real number d(u,v)=uvd(u,v)=\lVert u-v\rVert is a \reftext{def:metric-space-2026a}{metric} on VV.

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