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A Limit Computed from the Epsilon-Delta Definition

Beginner level. Verify the limit of x2x^2 at x=3x=3 straight from the epsilon-delta definition, by exhibiting a delta for each epsilon.

Statement

In the setting of The Real Line: Standing Notation and Background for Calculus on Intervals, in which R\mathbb{R} is recorded as an interval containing at least two points, let f:R→Rf:\mathbb{R}\to\mathbb{R} be given by

f(x)=x⋅x,f(x)=x\cdot x ,

which we also write x2x^2.

Problem. Show, directly from Limit of a Real Function at a Point of an Interval and without appealing to any theorem about limits or about continuity, that

lim⁡x→3f(x)=9.\lim_{x\to 3}f(x)=9 .

That is: for each real ε>0\varepsilon>0, exhibit a real δ>0\delta>0 such that every x∈Rx\in\mathbb{R} satisfying 0<∣x−3∣<δ0<|x-3|<\delta satisfies ∣x2−9∣<ε|x^2-9|<\varepsilon.

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