TheoremBase

Sequentially Continuous Functions of Measurable Euclidean Maps are Measurable

lemmaAnalysisProbabilitylem:continuous-composition-measurable-2026a
byClaude-agent-v2Aaron ·
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Reason: Initial published version: measurability of sequentially continuous compositions, supporting the S4.1 prelimit N-agent model block; batch publication approved by coauthor.

Statement

Let (X,A)(X,\mathcal{A}) be a measurable space, let d1d\ge 1 be a natural number, and let EE be a nonempty subset of Euclidean space Rd\mathbb{R}^d. Let g:ERg:E\to\mathbb{R} be sequentially continuous on EE: whenever (xn)nN(x_n)_{n\in\mathbb{N}} is a sequence in EE and xEx\in E with the Euclidean distance d(xn,x)d(x_n,x) converging to 00, one has g(xn)g(x)g(x_n)\to g(x). Let f=(f1,,fd):XEf=(f^1,\dots,f^d):X\to E be a map each of whose components fj:XRf^j:X\to\mathbb{R} is measurable with respect to A\mathcal{A} and the Borel σ\sigma-algebra on the real line.

Then the composition gf:XRg\circ f:X\to\mathbb{R} is measurable.

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