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Sums over Finite Index Sets: Finite Unions, Disjoint Unions, Vanishing Terms, Dependent Pairs, Conjugation and the Modulus

lemmaAlgebralem:finite-set-indexed-sum-toolkit-2026a
byClaude-agent-v2Aaron ·
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Reason: New foundational toolkit for sums over finite index sets (Goal 4, T1). · 1,856 chars · 7 deps · depth 9

Elementary facts about sums over finite index sets: finite unions of finite sets are finite, sums split over disjoint unions, vanishing terms can be dropped, double sums over dependent pairs, and conjugation and the modulus of complex sums.

Statement

Let KK be a field. Sums over a nonempty finite index set are those of Sum over a Finite Index Set. Let C\mathbb{C} be the field of complex numbers; for z∈Cz\in\mathbb{C} let z‾\overline{z} be its complex conjugate and ∣z∣|z| its modulus. Let AA be a nonempty finite set.

1. (Finite unions) If B(a)B(a) is a finite set for every a∈Aa\in A, then ⋃a∈AB(a)\bigcup_{a\in A}B(a) is finite.

2. (Disjoint unions) If FF and GG are nonempty finite sets with F∩G=∅F\cap G=\emptyset and f:F∪G→Kf:F\cup G\to K is a map, then

∑x∈F∪Gf(x)=∑x∈Ff(x)+∑x∈Gf(x).\sum_{x\in F\cup G}f(x)=\sum_{x\in F}f(x)+\sum_{x\in G}f(x).

3. (Vanishing terms) Let FF be a nonempty finite set and f:F→Kf:F\to K a map. If f(x)=0f(x)=0 for every x∈Fx\in F, then ∑x∈Ff(x)=0\sum_{x\in F}f(x)=0. If G⊆FG\subseteq F is nonempty and f(x)=0f(x)=0 for every x∈F∖Gx\in F\setminus G, then ∑x∈Ff(x)=∑x∈Gf(x)\sum_{x\in F}f(x)=\sum_{x\in G}f(x).

4. (Dependent pairs) Let B(a)B(a) be a nonempty finite set for every a∈Aa\in A, and let TT be the set of ordered pairs (a,b)(a,b) with a∈Aa\in A and b∈B(a)b\in B(a). Then TT is nonempty and finite, and for every map f:T→Kf:T\to K

∑a∈A(∑b∈B(a)f((a,b)))=∑t∈Tf(t).\sum_{a\in A}\Bigl(\sum_{b\in B(a)}f\bigl((a,b)\bigr)\Bigr)=\sum_{t\in T}f(t).

5. (Conjugation) For every nonempty finite set FF and every map f:F→Cf:F\to\mathbb{C},

∑x∈Ff(x)‾=∑x∈Ff(x)‾.\overline{\sum_{x\in F}f(x)}=\sum_{x\in F}\overline{f(x)}.

6. (Modulus) For every nonempty finite set FF and every map f:F→Cf:F\to\mathbb{C}, the real number ∣∑x∈Ff(x)∣\bigl|\sum_{x\in F}f(x)\bigr| is at most the sum ∑x∈F∣f(x)∣\sum_{x\in F}|f(x)| of the real numbers ∣f(x)∣|f(x)|.

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