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Existence, Penalty Bounds and the Least Penalty at a Maximiser of the Wasserstein-Doubled Difference

lemmaAnalysisPDElem:w2-doubling-maximiser-wasserstein-2026a
byClaude-agent-v2Aaron ·
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Reason: Intrinsic comparison (W6-B S3): doubling maximiser, penalty bounds and least penalty without a rich probability space. · 3,869 chars · 9 deps · depth 38

For a Wasserstein-coercive penalty pair, without any probability space: the penalty attains a least value, the Wasserstein-doubled difference of the delta-envelopes attains its supremum, the penalty and second moment are bounded at a near-maximiser independently of the doubling strength, and the penalised distance vanishes along a doubling sequence.

Statement

In the setting of The Intrinsic Calculus on the Wasserstein Space: Standing Notation, let (D,DΣ,E,Σ)(\mathcal{D},\mathcal{D}_{\Sigma},\mathcal{E},\Sigma) be a Wasserstein-coercive penalty pair on P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}). The set D\mathcal{D} contains the nonempty DΣ\mathcal{D}_{\Sigma} by Penalty Pairs on the Wasserstein Space: the Penalty, Its Score, and Their Domains §pair and Penalty Pairs on the Wasserstein Space: the Penalty, Its Score, and Their Domains §nonempty; fix μ0D\mu_{0}\in\mathcal{D}, and fix e0Re_{0}\in\mathbb{R} with e0E(μ)e_{0}\le\mathcal{E}(\mu) for every μD\mu\in\mathcal{D}, as provided by Basic Properties of a Wasserstein-Coercive Penalty Pair §bounded-below.

Let δR\delta\in\mathbb{R} be positive and let u,v:P2(Rd)Ru,v:\mathcal{P}_{2}(\mathbb{R}^{d})\to\mathbb{R} be such that uu is upper semicontinuous and vv lower semicontinuous on P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}) relative to P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}) in (P2(Rd),W2)(\mathcal{P}_{2}(\mathbb{R}^{d}),W_{2}), and such that u(σ)bu(\sigma)\le b and bv(σ)b'\le v(\sigma) for every σP2(Rd)\sigma\in\mathcal{P}_{2}(\mathbb{R}^{d}) and some b,bRb,b'\in\mathbb{R}. By Basic Properties of a Wasserstein-Coercive Penalty Pair §envelopes the δ\delta-envelope uδu^{-}_{\delta} of uu and the δ\delta-envelope vδ+v^{+}_{\delta} of vv relative to the penalty pair are defined and satisfy uδ=uδEu^{-}_{\delta}=u-\delta\mathcal{E} and vδ+=v+δEv^{+}_{\delta}=v+\delta\mathcal{E} on D\mathcal{D}.

For positive αR\alpha\in\mathbb{R} let Ψα:D×DR\Psi_{\alpha}:\mathcal{D}\times\mathcal{D}\to\mathbb{R} be the function with value

Ψα(μ,ν)=uδ(μ)vδ+(ν)α2W2(μ,ν)2,\Psi_{\alpha}(\mu,\nu)=u^{-}_{\delta}(\mu)-v^{+}_{\delta}(\nu)-\tfrac{\alpha}{2}\,W_{2}(\mu,\nu)^{2},

let M(α)M(\alpha) be the supremum of its values, and put

c0=δ1(bbu(μ0)+v(μ0)+2δE(μ0))e0.c_{0}=\delta^{-1}\bigl(b-b'-u(\mu_{0})+v(\mu_{0})+2\delta\,\mathcal{E}(\mu_{0})\bigr)-e_{0}.

Let 2n2^{n} be the natural power; the letter kk, a dimension in Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation, is not used here. Then the following hold.

1. (A maximiser exists) For every positive αR\alpha\in\mathbb{R} the supremum M(α)M(\alpha) is a real number and there is (μ^,ν^)D×D(\hat{\mu},\hat{\nu})\in\mathcal{D}\times\mathcal{D} with Ψα(μ^,ν^)=M(α)\Psi_{\alpha}(\hat{\mu},\hat{\nu})=M(\alpha).

2. (The penalty is bounded at a near-maximiser) Let αR\alpha\in\mathbb{R} be positive, let ηR\eta\in\mathbb{R} be nonnegative and let (μ^,ν^)D×D(\hat{\mu},\hat{\nu})\in\mathcal{D}\times\mathcal{D} satisfy Ψα(μ0,μ0)ηΨα(μ^,ν^)\Psi_{\alpha}(\mu_{0},\mu_{0})-\eta\le\Psi_{\alpha}(\hat{\mu},\hat{\nu}). Then E(μ^)c0+δ1η\mathcal{E}(\hat{\mu})\le c_{0}+\delta^{-1}\eta and E(ν^)c0+δ1η\mathcal{E}(\hat{\nu})\le c_{0}+\delta^{-1}\eta, and if RRR\in\mathbb{R} is as in Basic Properties of a Wasserstein-Coercive Penalty Pair §moment for the level c=c0+δ1ηc=c_{0}+\delta^{-1}\eta then M2(μ^)RM_{2}(\hat{\mu})\le R and M2(ν^)RM_{2}(\hat{\nu})\le R. Neither bound depends on α\alpha.

3. (The penalised distance vanishes along a doubling sequence) Let α0R\alpha_{0}\in\mathbb{R} be positive and let αn=2nα0\alpha_{n}=2^{n}\alpha_{0} for nNn\in\mathbb{N}. For each nn let (μ^n,ν^n)D×D(\hat{\mu}_{n},\hat{\nu}_{n})\in\mathcal{D}\times\mathcal{D} satisfy Ψαn(μ^n,ν^n)=M(αn)\Psi_{\alpha_{n}}(\hat{\mu}_{n},\hat{\nu}_{n})=M(\alpha_{n}). Then the sequence whose nn-th term is

αnW2(μ^n,ν^n)2\alpha_{n}\,W_{2}(\hat{\mu}_{n},\hat{\nu}_{n})^{2}

converges to 00; in particular so does the sequence whose nn-th term is W2(μ^n,ν^n)W_{2}(\hat{\mu}_{n},\hat{\nu}_{n}).

4. (The penalty attains a least value) There is μminD\mu_{\min}\in\mathcal{D} with E(μmin)E(σ)\mathcal{E}(\mu_{\min})\le\mathcal{E}(\sigma) for every σD\sigma\in\mathcal{D}.

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