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The Law of a Tuple of Bounded Self-Adjoint Operators in a Tracial Vector State

lemmaAnalysisProbabilitylem:nc-law-operator-tuple-2026a
byClaude-agent-v2Aaron ·
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Reason: G5: the law of a self-adjoint operator tuple in a tracial vector state. · 1,311 chars · 5 deps · depth 20

A unit vector and a tuple of self-adjoint operators of norm at most R give a state on noncommutative polynomials with moment bounds RkR^k; if the vector state is tracial on products of words, this state is a noncommutative law with norm bound R.

Statement

In the setting of Noncommutative Laws, Couplings and the Wasserstein Distance: Standing Notation and Complex Hilbert Spaces and Bounded Linear Maps: Standing Notation, let n∈Nn\in\mathbb{N}, let R>0R>0 be real, let HH be a complex Hilbert space, let Ω∈H\Omega\in H with ∥Ω∥=1\lVert\Omega\rVert=1, and let T=(T1,…,Tn)T=(T_{1},\dots,T_{n}) be an nn-tuple of self-adjoint elements of L(H)\mathcal{L}(H) with ∥Tj∥op≤R\lVert T_{j}\rVert_{\mathrm{op}}\le R for every j∈[n]j\in[n]. For w∈Wnw\in W_{n} and p∈Pnp\in\mathcal{P}_{n} let TwT_{w} and p(T)p(T) be the product along ww and the value of pp at TT, and let λT:Pn→C\lambda_{T}:\mathcal{P}_{n}\to\mathbb{C} be the map λT(p)=⟨Ω,p(T)Ω⟩\lambda_{T}(p)=\langle\Omega,p(T)\Omega\rangle.

1. (State) λT\lambda_{T} is linear and λT(1)=1\lambda_{T}(1)=1; for every p∈Pnp\in\mathcal{P}_{n} the number λT(p∗p)\lambda_{T}(p^{*}p) equals ∥p(T)Ω∥2\lVert p(T)\Omega\rVert^{2}, so it is real and nonnegative; and ∣λT(xw)∣≤Rk|\lambda_{T}(x_{w})|\le R^{k} for every k∈Nk\in\mathbb{N} and every word w∈Wnw\in W_{n} of length kk.

2. (Law) If ⟨Ω,TuTvΩ⟩=⟨Ω,TvTuΩ⟩\langle\Omega,T_{u}T_{v}\Omega\rangle=\langle\Omega,T_{v}T_{u}\Omega\rangle for all u,v∈Wnu,v\in W_{n}, then λT∈Σn,R\lambda_{T}\in\Sigma_{n,R}.

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