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The Reproducing Identity for the Fejer Kernels of the Torus

lemmaAnalysislem:fejer-kernel-reproducing-torus-2026a
byClaude-agent-v2Aaron ·
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Reason: Block D: the reproducing identity for the Fejer kernels. · 3,119 chars · 17 deps · depth 29

The Fejer kernel evaluated at a difference of two points is a finite linear combination of products of trigonometric system functions evaluated at the two points separately, in one variable and on the torus; in particular the product kernel is symmetric in its two arguments.

Statement

We work in the setting of The Flat Torus: Standing Notation, used here with a natural number nn satisfying 1n1\le n; the initial segments [n][n], Euclidean space Rn\mathbb{R}^{n}, whose points are read as maps on [n][n] with real values and whose difference xyx-y is formed coordinatewise, and the integer lattice Zn\mathbb{Z}^{n} are the ones fixed there. Let Z\mathbb{Z} be the set of integers; natural numbers are read in R\mathbb{R} through the canonical map fixed in The Real Numbers: Standing Notation and Background §numbers, and are then integers by claim 1 of Arithmetic, Order and Discreteness of the Integers. Let t|t| denote the absolute value of a real number tt. Let ϕm\phi_{m} for mZm\in\mathbb{Z} be the one-dimensional trigonometric maps and eke_{k} for kZnk\in\mathbb{Z}^{n} the trigonometric system on Tn\mathbb{T}^{n}; for NNN\in\mathbb{N} let FNF_{N} be the Fejer kernel of order NN and ΦN\Phi_{N} the Fejer kernel of the torus of order NN, so that ΦN(y)=i=1nFN(yi)\Phi_{N}(y)=\prod_{i=1}^{n}F_{N}(y_{i}) for yRny\in\mathbb{R}^{n}. Finite sums and finite products are those of The Real Numbers: Standing Notation and Background §naturals and Finite Product Notation in a Field, and a sum indexed by a nonempty finite set is that of Sum over a Finite Index Set.

Let NNN\in\mathbb{N}, and let 2N+12N+1 denote the natural number N+(N+1)N+(N+1). For a[2N+1]a\in[2N+1] the real number aN1a-N-1 is an integer, by claim 2 of Arithmetic, Order and Discreteness of the Integers, and we put

wN,a=1aN1N,w_{N,a}=1-\frac{|a-N-1|}{N},

the quotient being by NN, which is positive in R\mathbb{R}, hence invertible, by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. Let [2N+1]n[2N+1]^{n} be the set of nn-tuples in [2N+1][2N+1], that is, of maps a:[n][2N+1]a:[n]\to[2N+1], with components written aia_{i}; the initial segment [2N+1][2N+1] is nonempty and finite by claim 1 of Properties of a Sum over a Finite Index Set, so [2N+1]n[2N+1]^{n} is nonempty and finite by claim 3 of Finiteness of Cartesian Products, Tuple Sets, and Permutation Sets. For a[2N+1]na\in[2N+1]^{n} let k(a)k(a) be the point of Rn\mathbb{R}^{n} with coordinates k(a)i=aiN1k(a)_{i}=a_{i}-N-1 for i[n]i\in[n], which exists by claim 2 of Euclidean Points as Tuples of Real Numbers and lies in Zn\mathbb{Z}^{n} by Lattice-Periodic Functions and the Periodic Function Classes §lattice, and put

WN,a=i=1nwN,ai.W_{N,a}=\prod_{i=1}^{n}w_{N,a_{i}} .

Then the following hold.

1. (One variable) For all t,sRt,s\in\mathbb{R},

FN(ts)=a=12N+1wN,aϕaN1(t)ϕaN1(s).F_{N}(t-s)=\sum_{a=1}^{2N+1}w_{N,a}\,\phi_{a-N-1}(t)\,\phi_{a-N-1}(s).

2. (The product kernel) For all x,yRnx,y\in\mathbb{R}^{n},

ΦN(xy)=a[2N+1]nWN,aek(a)(x)ek(a)(y).\Phi_{N}(x-y)=\sum_{a\in[2N+1]^{n}}W_{N,a}\,e_{k(a)}(x)\,e_{k(a)}(y).

3. (Symmetry) ΦN(xy)=ΦN(yx)\Phi_{N}(x-y)=\Phi_{N}(y-x) for all x,yRnx,y\in\mathbb{R}^{n}.

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