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The Dirichlet and Fejer Kernel Identities

Multiplying the Dirichlet sum by the sine of pi t collapses it to a single sine of an odd multiple, and multiplying the Fejer sum by the square of that sine collapses it to the square of a sine; both are proved by induction on the number of terms.

Statement

In the setting of The Real Numbers: Standing Notation and Background, let cos⁡\cos and sin⁡\sin be the cosine and sine functions from R\mathbb{R} to R\mathbb{R}, let π\pi be the real number of The Number Pi (i), let 2=1+12=1+1, and for a real number tt let t2=ttt^{2}=tt as in The Real Numbers: Standing Notation and Background (i). Natural numbers are read in R\mathbb{R} through the canonical map fixed there, so that N−mN-m and 2N+12N+1 below denote real numbers. Finite sums are those of The Real Numbers: Standing Notation and Background (ii). Then the following hold for every N∈NN\in\mathbb{N} and every t∈Rt\in\mathbb{R}.

1. (The Dirichlet identity)

(1+2∑m=1Ncos⁡(2πmt))sin⁡(πt)=sin⁡((2N+1)πt).\Bigl(1+2\sum_{m=1}^{N}\cos(2\pi mt)\Bigr)\sin(\pi t)=\sin\bigl((2N+1)\pi t\bigr).

2. (The Fejer identity)

(N+2∑m=1N(N−m)cos⁡(2πmt))(sin⁡(πt))2=(sin⁡(Nπt))2.\Bigl(N+2\sum_{m=1}^{N}(N-m)\cos(2\pi mt)\Bigr)\bigl(\sin(\pi t)\bigr)^{2}=\bigl(\sin(N\pi t)\bigr)^{2}.

The coefficient N−mN-m of the summand at m=Nm=N is zero, so that summand vanishes and the sum involves only the cosines with m<Nm<N; writing the sum up to NN rather than up to N−1N-1 avoids an empty sum when N=1N=1.

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