TheoremBase

The Radial Compactification of Euclidean Space: Norm Continuity, a Homeomorphism onto the Open Unit Ball, Radial Cutoffs, and Extension of Test Functions

The map sending x to x divided by one plus its norm is a homeomorphism of Euclidean space onto the open unit ball; compact sets are carried into balls of radius less than one, radial cutoffs are available there, and multiplying a continuous function by such a cutoff produces a continuous function on the closed unit ball.

Statement

In the setting of Probability Measures on Euclidean Space and Random Vectors: Standing Notation, let m∈Nm\in\mathbb{N} satisfy 1≤m1\le m, let ∥⋅∥\lVert\cdot\rVert be the Euclidean norm on Rm\mathbb{R}^{m} and dEd_{E} the Euclidean distance, related by dE(x,y)=∥x−y∥d_{E}(x,y)=\lVert x-y\rVert through claim 2 of Properties of the Euclidean Norm on Rn\mathbb{R}^n: Square, Distance, Vanishing, Coordinate Bounds, Homogeneity, Triangle Inequalities and Expansion of a Square, and let T\mathcal{T} be the collection of subsets of Rm\mathbb{R}^{m} that are open in (Rm,dE)(\mathbb{R}^{m},d_{E}), a topology by The Open Subsets of a Metric Space Form a Topology. Let R\mathbb{R} carry the absolute-value metric dRd_{\mathbb{R}}, and write 2=1+12=1+1.

Put

Bˉ={y∈Rm:∥y∥≤1},U={y∈Rm:∥y∥<1},\bar{B}=\{y\in\mathbb{R}^{m}:\lVert y\rVert\le 1\},\qquad U=\{y\in\mathbb{R}^{m}:\lVert y\rVert<1\},

let dBˉd_{\bar{B}} and dUd_{U} be the restrictions of dEd_{E} to Bˉ\bar{B} and to UU, and define

h:Rm→Rm,h(x)=(1+∥x∥)−1x,g:U→Rm,g(y)=(1−∥y∥)−1y,h:\mathbb{R}^{m}\to\mathbb{R}^{m},\quad h(x)=\bigl(1+\lVert x\rVert\bigr)^{-1}x,\qquad g:U\to\mathbb{R}^{m},\quad g(y)=\bigl(1-\lVert y\rVert\bigr)^{-1}y ,

the two inverses existing because 0<1+∥x∥0<1+\lVert x\rVert and 0<1−∥y∥0<1-\lVert y\rVert for x∈Rmx\in\mathbb{R}^{m} and y∈Uy\in U.

Then the following hold.

1. (Continuity of the norm) The map N:Rm→RN:\mathbb{R}^{m}\to\mathbb{R} with N(x)=∥x∥N(x)=\lVert x\rVert is Lipschitz with constant 11 from (Rm,dE)(\mathbb{R}^{m},d_{E}) to (R,dR)(\mathbb{R},d_{\mathbb{R}}), and is continuous on Rm\mathbb{R}^{m}.

2. (The closed and the open unit ball) Bˉ\bar{B} is the closed ball of (Rm,dE)(\mathbb{R}^{m},d_{E}) with centre 00 and radius 11, and UU is the open ball with the same centre and radius. The set Bˉ\bar{B} is nonempty and compact in (Rm,T)(\mathbb{R}^{m},\mathcal{T}), and the metric space (Bˉ,dBˉ)(\bar{B},d_{\bar{B}}) is compact. Moreover U∈TU\in\mathcal{T}, U⊆BˉU\subseteq\bar{B}, and UU is open in the metric space (Bˉ,dBˉ)(\bar{B},d_{\bar{B}}).

3. (A homeomorphism onto the open unit ball) For every x∈Rmx\in\mathbb{R}^{m} one has ∥h(x)∥=(1+∥x∥)−1∥x∥<1\lVert h(x)\rVert=(1+\lVert x\rVert)^{-1}\lVert x\rVert<1, so that h(x)∈Uh(x)\in U. The map hh is a bijection from Rm\mathbb{R}^{m} onto UU whose inverse is gg. Furthermore hh is Lipschitz with constant 22, hence continuous on Rm\mathbb{R}^{m}, as a map into (Rm,dE)(\mathbb{R}^{m},d_{E}), and gg is continuous on UU as a map from (U,dU)(U,d_{U}) into (Rm,dE)(\mathbb{R}^{m},d_{E}).

4. (Images of compact sets) Let K⊆RmK\subseteq\mathbb{R}^{m} be nonempty and compact in (Rm,T)(\mathbb{R}^{m},\mathcal{T}). Then there is ρ∈R\rho\in\mathbb{R} with 0≤ρ<10\le\rho<1 such that ∥h(x)∥≤ρ\lVert h(x)\rVert\le\rho for every x∈Kx\in K.

5. (Radial cutoffs) Let ρ∈R\rho\in\mathbb{R} satisfy 0≤ρ<10\le\rho<1 and put σ=2−1(1+ρ)\sigma=2^{-1}(1+\rho). Then ρ<σ<1\rho<\sigma<1, and the map χ:Rm→R\chi:\mathbb{R}^{m}\to\mathbb{R} given by

χ(y)=min⁡{1, max⁡{0, (σ−ρ)−1(σ−∥y∥)}}\chi(y)=\min\bigl\{1,\ \max\{0,\ (\sigma-\rho)^{-1}(\sigma-\lVert y\rVert)\}\bigr\}

is continuous on Rm\mathbb{R}^{m} and satisfies 0≤χ(y)≤10\le\chi(y)\le 1 for every y∈Rmy\in\mathbb{R}^{m}, χ(y)=1\chi(y)=1 whenever ∥y∥≤ρ\lVert y\rVert\le\rho, and χ(y)=0\chi(y)=0 whenever σ≤∥y∥\sigma\le\lVert y\rVert.

6. (Extension of a test function to the closed unit ball) Let ρ\rho, σ\sigma and χ\chi be as in clause 5, and let f:Rm→Rf:\mathbb{R}^{m}\to\mathbb{R} be continuous on Rm\mathbb{R}^{m}. Define F:Bˉ→RF:\bar{B}\to\mathbb{R} by

F(y)=χ(y) f(g(y))for y∈U,F(y)=0for y∈Bˉ∖U.F(y)=\chi(y)\,f(g(y))\quad\text{for }y\in U,\qquad F(y)=0\quad\text{for }y\in\bar{B}\setminus U .

Then F(y)=0F(y)=0 for every y∈Bˉy\in\bar{B} with σ≤∥y∥\sigma\le\lVert y\rVert; the map FF is continuous on Bˉ\bar{B} as a map from (Bˉ,dBˉ)(\bar{B},d_{\bar{B}}) to (R,dR)(\mathbb{R},d_{\mathbb{R}}); one has F(h(x))=χ(h(x)) f(x)F(h(x))=\chi(h(x))\,f(x) for every x∈Rmx\in\mathbb{R}^{m}; and if M∈RM\in\mathbb{R} satisfies ∣f(x)∣≤M|f(x)|\le M for every x∈Rmx\in\mathbb{R}^{m}, then ∣F(y)∣≤M|F(y)|\le M for every y∈Bˉy\in\bar{B}.

Proofs

Log in to submit a proof.

Loading...

Citations

Loading…

Dependencies

Loading…

Related

0 relations

Curated associations between results. These are editable and subjective — they do not replace the dependency graph, which is derived from the references in the text.

No relations recorded yet.

Comments

Log in to comment.

Loading…