The Radial Compactification of Euclidean Space: Norm Continuity, a Homeomorphism onto the Open Unit Ball, Radial Cutoffs, and Extension of Test Functions
lemmaAnalysisTopologylem:radial-compactification-euclidean-2026aThe map sending x to x divided by one plus its norm is a homeomorphism of Euclidean space onto the open unit ball; compact sets are carried into balls of radius less than one, radial cutoffs are available there, and multiplying a continuous function by such a cutoff produces a continuous function on the closed unit ball.
In the setting of Probability Measures on Euclidean Space and Random Vectors: Standing Notation, let satisfy , let be the Euclidean norm on and the Euclidean distance, related by through claim 2 of Elementary Properties of the Euclidean Norm on , and let be the collection of subsets of that are open in , a topology by Metric Open Sets Form a Topology. Let carry the absolute-value metric , and write .
Put
let and be the restrictions of to and to , and define
the two inverses existing because and for and .
Then the following hold.
1. (Continuity of the norm)¶ The map with is Lipschitz with constant from to , and is continuous on .
2. (The closed and the open unit ball)¶ is the closed ball of with centre and radius , and is the open ball with the same centre and radius. The set is nonempty and compact in , and the metric space is compact. Moreover , , and is open in the metric space .
3. (A homeomorphism onto the open unit ball)¶ For every one has , so that . The map is a bijection from onto whose inverse is . Furthermore is Lipschitz with constant , hence continuous on , as a map into , and is continuous on as a map from into .
4. (Images of compact sets)¶ Let be nonempty and compact in . Then there is with such that for every .
5. (Radial cutoffs)¶ Let satisfy and put . Then , and the map given by
is continuous on and satisfies for every , whenever , and whenever .
6. (Extension of a test function to the closed unit ball)¶ Let , and be as in clause 5, and let be continuous on . Define by
Then for every with ; the map is continuous on as a map from to ; one has for every ; and if satisfies for every , then for every .
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