TheoremBase

The Lebesgue Density Theorem in Rn\mathbb{R}^n

Almost every point of an arbitrary subset of Euclidean space is a density point of that subset; no measurability of the set is assumed, the statement being formulated with Lebesgue outer measure.

Statement

We work in the setting of Product Measures and Lebesgue Measure on ℝⁿ: Standing Notation and Background, whose notation is fixed for every dimension and is used here with a natural number nn satisfying 1≤n1\le n: the Euclidean norm, distance, topology, notion of openness and closed balls Bˉ(x,r)\bar{B}(x,r) of Rn\mathbb{R}^{n}, the Borel σ\sigma-algebra B(Rn)\mathcal{B}(\mathbb{R}^{n}), Lebesgue measure λn\lambda_{n}, and the notion of a null subset of Rn\mathbb{R}^{n} are as fixed there. Write λn∗\lambda_{n}^{\ast} for Lebesgue outer measure, and let density point have the meaning fixed in that definition.

Let E⊆RnE\subseteq\mathbb{R}^{n} be an arbitrary subset. Then the following holds.

1. (Almost every point of a set is a density point of it) The set of those x∈Ex\in E which are not density points of EE is null.

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