TheoremBase

L²(μ) Is a Real Hilbert Space

The integral of the product is an inner product on the Lebesgue space of square-integrable classes, its induced norm is the 2-norm, and under dependent choice the space is a real Hilbert space.

Statement

In the settings of Measurable Functions and the Lebesgue Integral: Standing Notation and Real Normed, Inner Product and Hilbert Spaces: Notation, let (X,F,μ)(X,\mathcal{F},\mu) be a measure space. Let L2(μ)L^{2}(\mu) be the Lebesgue space with p=2p=2, with the addition and scalar multiplication of The Lebesgue Space Lᵖ(μ) (ii), the norm ∥⋅∥2\|\cdot\|_{2} of The Lebesgue Space Lᵖ(μ) (iii) and the inner product ⟨⋅,⋅⟩\langle\cdot,\cdot\rangle of The Lebesgue Space Lᵖ(μ) (iv).

An inner product space. L2(μ)L^{2}(\mu), with ⟨⋅,⋅⟩\langle\cdot,\cdot\rangle, is a real inner product space.

The induced norm. The induced norm of L2(μ)L^{2}(\mu) is ∥⋅∥2\|\cdot\|_{2}:

⟨F,F⟩=∥F∥2(F∈L2(μ)).\sqrt{\langle F,F\rangle}=\|F\|_{2}\qquad(F\in L^{2}(\mu)).

A Hilbert space. Assume the axiom of dependent choice. Then L2(μ)L^{2}(\mu) is a real Hilbert space.

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