In the setting of Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation, assume that (Ω,F,P) is rich, which Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §background does not assume, and let (D,DΣ,E,Σ) be a Wasserstein-coercive penalty pair on P2(Rd). The set D contains the nonempty DΣ by Penalty Pairs on the Wasserstein Space: the Penalty, Its Score, and Their Domains §pair and Penalty Pairs on the Wasserstein Space: the Penalty, Its Score, and Their Domains §nonempty; fix μ0∈D, and fix e0∈R with e0≤E(μ) for every μ∈D, as provided by Basic Properties of a Wasserstein-Coercive Penalty Pair §bounded-below.
Let δ∈R be positive and let u,v:P2(Rd)→R be such that u is upper semicontinuous and v lower semicontinuous on P2(Rd) relative to P2(Rd) in (P2(Rd),W2), and such that u(σ)≤b and b′≤v(σ) for every σ∈P2(Rd) and some b,b′∈R. By Basic Properties of a Wasserstein-Coercive Penalty Pair §envelopes the δ-envelope uδ− of u and the δ-envelope vδ+ of v relative to the penalty pair are defined and satisfy uδ−=u−δE and vδ+=v+δE on D.
For positive α∈R let Ψα:D×D→R be the function with value
Ψα(μ,ν)=uδ−(μ)−vδ+(ν)−2αW2(μ,ν)2,
let M(α) be the supremum of its values, and put
c0=δ−1(b−b′−u(μ0)+v(μ0)+2δE(μ0))−e0.
Write DΛ for the preimage of D under the law map, and let 2n be the natural power; the letter k, a dimension in Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation, is not used here. Then the following hold.
1. (A maximiser exists)¶ For every positive α∈R the supremum M(α) is a real number and there is (μ^,ν^)∈D×D with Ψα(μ^,ν^)=M(α).
2. (The penalty is bounded at a near-maximiser)¶ Let α∈R be positive, let η∈R be nonnegative and let (μ^,ν^)∈D×D satisfy Ψα(μ0,μ0)−η≤Ψα(μ^,ν^). Then E(μ^)≤c0+δ−1η and E(ν^)≤c0+δ−1η, and if R∈R is as in Basic Properties of a Wasserstein-Coercive Penalty Pair §moment for the level c=c0+δ−1η then M2(μ^)≤R and M2(ν^)≤R. Neither bound depends on α.
3. (The penalised distance vanishes along a doubling sequence)¶ Let α0∈R be positive and let αn=2nα0 for n∈N. For each n let (μ^n,ν^n)∈D×D satisfy Ψαn(μ^n,ν^n)=M(αn). Then the sequence whose n-th term is
αnW2(μ^n,ν^n)2
converges to 0; in particular so does the sequence whose n-th term is W2(μ^n,ν^n).
4. (Realisation by an optimally coupled pair)¶ Let α∈R be positive and let (μ^,ν^)∈D×D satisfy Ψα(μ^,ν^)=M(α). Then there are X^,Y^∈DΛ with L(X^)=μ^, L(Y^)=ν^ and
∥X^−Y^∥L2=W2(μ^,ν^),
and for any such pair the law of the pairing (X^,Y^) is an optimal coupling of μ^ and ν^ and
uδ−(L(X))−vδ+(L(Y))−2α∥X−Y∥L22 ≤ uδ−(μ^)−vδ+(ν^)−2α∥X^−Y^∥L22
for all X,Y∈DΛ.
5. (The two one-variable extrema)¶ Let α, (μ^,ν^) and X^,Y^ be as in claim 4. Then the function DΛ→R with value uδ−(L(X))−2α∥X−Y^∥L22 at X attains at X^ a value at least its value at every point of DΛ, and the function DΛ→R with value vδ+(L(Y))+2α∥X^−Y∥L22 at Y attains at Y^ a value at most its value at every point of DΛ. In particular the first has a local maximum at X^ relative to DΛ and the second a local minimum at Y^ relative to DΛ, in the metric space (L2(Ω;Rd),dL2).