TheoremBase

Comparison of a Viscosity Subsolution with a Strict Classical Supersolution

On a bounded domain, a viscosity subsolution of a proper operator lies below any lower semicontinuous strict classical supersolution that dominates it on the boundary.

Statement

In the setting of Second-Order Equations on Euclidean Open Sets and of Bounded Open Domain in Euclidean Space, let FF be a second-order equation operator on Ω\Omega that is proper.

Let u:Ω‾→Ru:\overline{\Omega}\to\mathbb{R} be a viscosity subsolution of FF up to the boundary of Ω\Omega.

Let v:Ω‾→Rv:\overline{\Omega}\to\mathbb{R} be lower semicontinuous on Ω‾\overline{\Omega}, and let v∣Ω:Ω→Rv|_{\Omega}:\Omega\to\mathbb{R}, the function whose value at x∈Ωx\in\Omega is v(x)v(x), be of class C2C^{2} on Ω\Omega. For x∈Ωx\in\Omega write Dv(x)Dv(x) for the gradient and D2v(x)D^{2}v(x) for the Hessian of v∣Ωv|_{\Omega} at xx; by that clause D2v(x)∈S(n)D^{2}v(x)\in\mathcal{S}(n), so the quadruple (x,v(x),Dv(x),D2v(x))(x,v(x),Dv(x),D^{2}v(x)) lies in the domain of FF.

Assume the following two conditions.

1. (Strict supersolution inequality) 0<F(x,v(x),Dv(x),D2v(x))0<F(x,v(x),Dv(x),D^{2}v(x)) for every x∈Ωx\in\Omega.

2. (Boundary inequality) u(x)≤v(x)u(x)\le v(x) for every x∈∂Ωx\in\partial\Omega.

Then u(x)≤v(x)u(x)\le v(x) for every x∈Ω‾x\in\overline{\Omega}.

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