TheoremBase

Conjugate Exponents and Young's Inequality

Every real exponent p > 1 has a unique conjugate exponent q > 1 with 1/p + 1/q = 1, and for such p, q and nonnegative a, b the product ab is at most ap/pa^p/p + bq/qb^q/q.

Statement

In the setting of The Real Line: Standing Notation and Background for Calculus on Intervals, let tat^{a}, for real t≥0t\ge0 and a>0a>0, be the real power of Real Powers.

Conjugate exponents. Let p>1p>1 be a real number. Then q=p/(p−1)q=p/(p-1) is the unique real number with

1p+1q=1,\frac{1}{p}+\frac{1}{q}=1,

and q>1q>1.

Young's inequality. Let p,q>1p,q>1 be real numbers with 1/p+1/q=11/p+1/q=1, and let a,b≥0a,b\ge0 be real numbers. Then

ab≤app+bqq.ab\le\frac{a^{p}}{p}+\frac{b^{q}}{q} .

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